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svet-max [94.6K]
3 years ago
15

Give an example of something moving that is not accelerating

Physics
1 answer:
Anastaziya [24]3 years ago
6 0
Anything that doesnt have a change in magnitude or direction is something thats not accelerating. so, for example, a car moving at a constant speed of 5mph on a flat road is an example of an object moving but not accelerating
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A material the resists the flow of electrons is called a
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An insulator which is also called a 'dielectric'.
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-4, 0, -2/3, 4.11111…, 2, π, √6 'which members of this set are irrartional?
krok68 [10]

An irrational number is a real number that cannot be written as a simple fraction.

4 = 4/1 = rational

0 = 0/1 = rational

-2/3 = rational

4.11111 = irrational

2 = 2/1 = rational

π = 3.141592... = irrational

√6= irrational

Answer:

4.1111, π , √6

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386.5<br>- 129.18 what is it​
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257.32

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How much of the Moon is always illuminated one time? Explain your answer.
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3 years ago
A 0.750 kg block is attached to a spring with spring constant 17.5 N/m. While the block is sitting at rest, a student hits it wi
Dmitriy789 [7]

Answer:

a

 A =  0.081 \  m

b

The value is  u =  0.2569 \  m/s

Explanation:

From the question we are told that

   The mass is  m  =  0.750 \ kg

   The spring constant is  k  =  17.5 \  N/m

    The instantaneous speed is  v  =  39.0 \  cm/s= 0.39 \  m/s

    The position consider is  x =  0.750A  meters from equilibrium point

   

Generally from the law of  energy conservation we have that

        The kinetic energy induced by the hammer  =  The energy stored in the spring

So

          \frac{1}{2} *  m * v^2  =  \frac{1}{2}  *  k  *  A^2

Here a is the amplitude of the subsequent oscillations

=>      A =  \sqrt{\frac{m *  v^ 2 }{ k} }

=>      A =  \sqrt{\frac{0.750 *  0.39 ^ 2 }{17.5} }

=>       A =  0.081 \  m

Generally from the law of  energy conservation we have that

The kinetic energy  by the hammer  =  The energy stored in the spring at the point considered   +   The kinetic energy at the considered point

             \frac{1}{2}  * m *  v^2 = \frac{1}{2}  * k x^2 + \frac{1}{2}  * m *  u^2

=>          \frac{1}{2}  * 0.750 *  0.39^2 = \frac{1}{2}  * 17.5* 0.750(0.081 )^2 + \frac{1}{2}  * 0.750 *  u^2

=>          u =  0.2569 \  m/s

3 0
2 years ago
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