1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
svet-max [94.6K]
3 years ago
15

Give an example of something moving that is not accelerating

Physics
1 answer:
Anastaziya [24]3 years ago
6 0
Anything that doesnt have a change in magnitude or direction is something thats not accelerating. so, for example, a car moving at a constant speed of 5mph on a flat road is an example of an object moving but not accelerating
You might be interested in
IN WHAT CONDITION DO SOUND ECHO
DerKrebs [107]

Answer:

The conditions necessary for hearing the echo. The distance between the sound source and the reflecting surface must not be less than 17 metres where the time period between hearing the original sound and its echo should not be less than 0.1 of a second.

6 0
2 years ago
That which flows on uniformly, of which a day is a logical portion, is called time. True or False
mr_godi [17]
The answer to the statement is true because the day is of the logical proportion it has to be time.
3 0
3 years ago
Read 2 more answers
1. Straight-in spaces can leave you a safer out if
Juliette [100K]

Answer:

C. you're able to reverse out of the parking spot

Explanation:

Straight-in parking is an approach of parking that allows a more flexible traffic layout where a driver can approach the spot from either direction and still safely park within the lines. It thus helps to prevent blockage of cars. Each car can move in and out freely preventing it from congestion.

This way of parking can leave you safe when you able to reverse out of the parking spot. It gives you greater control and makes it easier to maneuver out space. The benefits of Straight-in parking are,

- Allows for two-way traffic

- Drivers can line up the vehicle from multiple angles

- Saves time for drivers

3 0
3 years ago
A professor drives off with his car (mass 870 kg), but forgot to take his coffee mug (mass 0.47 kg) off the roof. The coefficien
SSSSS [86.1K]

Answer:6.86 m/s^2

Explanation:

Given

mas of car=870 kg

coffee mug mass=0.47 kg

coefficient of static friction between mug and roof \mu _s= 0.7

Coefficient of kinetic Friction \mu _k=0.5

maximum car acceleration is \mu \times g

here coefficient of static friction comes in to action because mug is placed over car . If mug is moving relative to car then \mu _k is come into effect

a_{max}=0.7\times 9.8=6.86 m/s^2

8 0
3 years ago
Narysuj wykres zależności v(t) jeśli w chwili początkowej t=0 V=10m/s w każdej sekundzie szybkość zmniejsza się o 1m/s . Po jaki
irina1246 [14]

1) See graph in attachment

2) 10 s

3) 50 m

Explanation:

1)

In this problem, we have an object initially moving with a velocity of

v = 10 m/s

when the time is

t = 0 s

Then, we are told that the speed of the object is decreasing by 1 m/s every  second. This means that on a velocity-time graph, the motion will be represented by a straight line, starting from v = 10 when t = 0, and decreasing by 1 m/s every second.

The result can be found in the graph in attachment.

Moreover, we can also infer that the motion of the object is accelerated (because velocity is changing), and that the acceleration is constant and it is equal to

a=1 m/s^2

which is equivalent to the gradient of the line in the velocity-time graph.

2)

In this part, we want to find after what time the body will stop its motion.

To do that, we can use the following suvat equation:

v=u+at

where

v is the final velocity

u is the initial velocity

a is the acceleration

t is the time

In this problem:

u = 10 m/s is the initial velocity of the body

a=-1 m/s^2 is the acceleration

v = 0 m/s, because we want to find the time T at which the body will stop

Re-arranging the equation, we find:

T=-\frac{u}{a}=-\frac{10}{-1}=10 s

3)

In order to find the total distance covered by the body during its accelerated motion, we have to use another suvat equation:

s=ut+\frac{1}{2}at^2

where

s is the distance covered

u is the initial velocity

t is the time

a is the acceleration

In this problem:

u = 10 m/s is the initial velocity

a=-1 m/s^2 is the acceleration

t = 10 s is the time it takes for the body to stop (found in part 2)

Solving for s, we find the distance covered:

s=(10)(10)+\frac{1}{2}(-1)(10)^2=50 m

7 0
3 years ago
Other questions:
  • The momentum of an electron is 1.75 times larger than the value computed non-relativistically. What is the speed of the electron
    13·1 answer
  • Approximately how far is the sun from the center of the milky way galaxy?
    12·2 answers
  • What process modifies light waves to vibrate in a single plane
    12·1 answer
  • A scientist wants to calculate the kinetic energy of a cheetah as it chases down its prey. What does the scientist need to measu
    5·2 answers
  • The distance traveled by an ibject divided by thr time it takes to travel that distance is called?
    7·1 answer
  • Water is boiled at 300 kPa pressure in a pressure cooker. The cooker initially contains 3 kg of water. Once boiling started, it
    10·1 answer
  • A 40kg rock falls off a cliff that is 50 meters high. How fast is the speed of the rock when it hits the ground
    6·1 answer
  • Magnetic field strength decrease when what is increases
    13·1 answer
  • The electrical voltage between the ends of a resistor is equal to 8 V. A student has two voltmeters available that measure up to
    15·1 answer
  • 1. Is the image projected on a movie screen real or virtual? What about the image of yourself seen in a bathroom mirror?
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!