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ladessa [460]
2 years ago
9

What is the net force acting on a car cruising at a constant velocity of 70 km/h (a) on a level road, (b) on an uphill road?

Physics
1 answer:
xeze [42]2 years ago
6 0

The net force on the car for either case will be zero, since the car is moving at a constant velocity.

<h3>Net force on the car</h3>

The net force on the car is the sum of all the forces acting on the car.

∑F = ma

<h3>When the car is on a level road</h3>

When the car is on a level road, the only two forces acting on the car is the applied force and frictional force of the road.

F - Ff = 0

The net force will be zero, since the car is moving at a constant velocity.

<h3>When the car is on uphill</h3>

The forces acting on the car at the uphill is the applied force, weight of the car acting downwards and the frictional force acting opposite direction.

F - Wsinθ - μFₙcosθ = 0

The net force will be zero, since the car is moving at a constant velocity.

Learn more about net force at constant velocity here: brainly.com/question/14392124

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What is physical measurement? in Science​
Anvisha [2.4K]

Answer:

physical measurement comprises the measurement of objects, things, etc. and is concerned with the measurement of height, weight, length, size, volume etc.

5 0
3 years ago
A catapult with a spring constant of 10,000 N/m is used to launch a target from the deck of a ship. The spring is compressed a d
Mnenie [13.5K]

Answer:

(C) 40m/s

Explanation:

Given;

spring constant of the catapult, k = 10,000 N/m

compression of the spring, x = 0.5 m

mass of the launched object, m = 1.56 kg

Apply the principle of conservation of energy;

Elastic potential energy of the catapult = kinetic energy of the target launched.

¹/₂kx² = ¹/₂mv²

where;

v is the target's  velocity as it leaves the catapult

kx² = mv²

v² = kx² / m

v² = (10000 x 0.5²) / (1.56)

v² = 1602.56

v = √1602.56

v = 40.03 m/s

v ≅ 40 m/s

Therefore, the target's velocity as it leaves the spring is 40 m/s

6 0
2 years ago
A plank rests on top of the axles of two identical wheels. Each wheel's outer radius is 0.25 meters and each wheel's axle has ra
kaheart [24]

Answer:

<u><em>The plank moves 0.2m from it's original position</em></u>

Explanation:

we can do this question from the constraints that ,

  • the wheel and the axle have the same angular speed or velocity
  • the speed of the plank is equal to the speed of the axle at the topmost point .

thus ,

<em>since the wheel is pure rolling or not slipping,</em>

<em>⇒v=wr</em>

where

<em>v - speed of the wheel</em>

<em>w - angular speed of the wheel</em>

<em>r - radius of the wheel</em>

<em>since the wheel traverses 1 m let's say in time 't' ,</em>

<em>v_{w}=\frac{distance}{time} =\frac{1}{t}</em>

∴

⇒w=\frac{v_{w}}{r} = \frac{1}{t*0.25}

the speed at the topmost point of the axle is :

⇒v_{a}=w*r\\v_{a}=\frac{1}{t*0.25} *0.05\\v_{a}=\frac{1}{5t}

this is the speed of the plank too.

thus the distance covered by plank in time 't' is ,

⇒d=v_{a}*t\\d=\frac{1}{5t} *t\\d=\frac{1}{5} = 0.2m

8 0
3 years ago
A vitamin called folic acid is very important for neural tube development, which is the development of the baby's
Anestetic [448]

Answer:

Explanation:

Folic acid is the form of folate found in vitamin supplements and fortified foods. Fortified foods, also called enriched foods, are foods that have specific nutrients added to them.

Neural tube defect happen when the tissues and bone around the brain and spine do not grow well. Neural tube can happen in the third and fourth week after conception (the first or second week after your first missed period). This could be before you know that you are pregnant.

Folic acid lowers the risk of your unborn baby having a neural tube defect . Neural tube are a group of serious birth defects that affect a baby’s spinal cord, brain and skull. Some babies with severe Neural tube defect birth are stillborn or do not survive long after birth. Spina Bifida is the most common Neural tube defect.

3 0
3 years ago
An electron emitted from a filament is travelling at 1.5 x 105 m/s when it enters an acceleration of an electron gun in a televi
Crank

Answer:

The acceleration of the electron is 1.457 x 10¹⁵ m/s².

Explanation:

Given;

initial velocity of the emitted electron, u = 1.5 x 10⁵ m/s

distance traveled by the electron, d = 0.01 m

final velocity of the electron, v = 5.4 x 10⁶ m/s

The acceleration of the electron is calculated as;

v² = u² + 2ad

(5.4 x 10⁶)² = (1.5 x 10⁵)² + (2 x 0.01)a

(2 x 0.01)a = (5.4 x 10⁶)² - (1.5 x 10⁵)²

(2 x 0.01)a = 2.91375 x 10¹³

a = \frac{2.91375 \ \times \ 10^{13}}{2 \ \times \ 0.01} \\\\a = 1.457 \ \times \ 10^{15} \ m/s^2

Therefore, the acceleration of the electron is 1.457 x 10¹⁵ m/s².

7 0
3 years ago
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