Answer:
Gravity: downwards
Air drag and air-pressure on the inner surface of the the parachute: Upwards
Explanation:
- If a sky-diver is in the final stages of his descend with open parachute such that the wind is calm and it does not blows him laterally.
- In such a condition the air resistance in the form of drag and the pressure force due to the air captured in the parachute are acting in the upward direction which balance the force of gravity on the body. But this situation may occur momentarily and then again the diver must begin to slowly descend.
Answer:
Given that battery V = 12.0 V
Resistance R = 2.0 ohms
a ) current in the battery is I = V /R
= 12.0 V / 2.0
= 6.0 A
b ) charge transported in the circuit is q = i * t
= 6.0 A * 10 s
= 60 C
c ) Work done on the charge by the electric field is 0 ( there is no internal resistance )
d ) work done through the resistor is w = P * t
= ( V)^2 / R * t
= ( 12.0 V )^2 / 2 *10s
= 720J
e ) Total work done is equal to work done through the resistor
W_total = 720 J
f ) there is no internal resistance hence E = 0
I think fission chain reaction is the correct answer.
