The conjugate base of ch3ch2co2h or propanoic acid would be CH3CH2COO- or propanoate. The conjugate base is what is left after an acid has donated a proton in a reaction. Hope this answers the question. Have a nice day.
I believe that the correct answer is K.
Answer:
- Acid-Base reaction (the reactanct acting as a base is NaOH)
Explanation:
The reaction that takes place is:
- C₃H₅O(CO₂H)₃(aq) + 3OH⁻ (aq) → C₃H₅O(CO₂)₃⁻³(aq) + 3H₂O(l)
This is a <em>acid-base reaction</em>, with the citric acid acting as the acid and the <u>sodium hydroxide NaOH acting as the base.</u>
We <u>calculate the moles of citric acid</u> using the information from the titration:
- 0.0142 L * 0.340 M *
= 1.609x10⁻³ mol citric acid
Now we <u>convert moles to mass</u> using the acid's molecular weight (192.13g/mol):
- 1.609x10⁻³ mol citric acid * 192.13g/mol = 0.3092 g citric acid
Finally we calculate the mass percent of citric acid in the sample:
- 0.3092 g / 16.00 g * 100% = 1.93%
i believe the answer is...
Atoms of isotopes of an element have different numbers of protons.
Heat wise! And cooling too