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PolarNik [594]
4 years ago
8

How many loads of laundry will each shift pay for if the cost per load rises to 8 quarters?

Chemistry
1 answer:
Maksim231197 [3]4 years ago
3 0
The answer is 3 loads
You have<span> 0.2 shifts per 1 load.</span>
You have<span> 5 loads per 1 shift.</span>
So you have 3 loads for 8 quarters.
0.2 x 5 = 1
1 x 3 = 3. So the answer is 3 loads.
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Complete this equation for the dissociation of na2co3(aq). omit water from the equation because it is understood to be present.
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If a certain mass of mercury has a volume of 0.002 m2 at a temperature of 20 celsius, what will be the volume of 50 celsius?
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Answer: 0.0022m3

Explanation:

Initial volume of mercury V1 = 0.002m3 (note that the unit of volume can be cm3, m3, dm3 or liters)

Initial temperature T1 = 20°C

Convert temperature in Celsius to Kelvin

( 20°C + 273°C = 293K)

Final temperature T2 = 50°C

( 50°C + 273°C = 323K)

Final volume V2 = ?

According to Charle's law, the volume of a fixed mass of a gas is directly proportional to the temperature.

Mathematically, Charles' Law is expressed as: V1/T1 = V2/T2

0.002/293 = V2/323

To get the value of V2, cross multiply

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3 0
3 years ago
Determine the volume of Fe(NO3)3 stock solution needed to prepare a dilute solution (left side), then decide what volume of dilu
arsen [322]

Answer:

Here's what I get  

Explanation:

Assume you want to use 0.5 mL of a stock solution with a concentration of 0.2 mol·L⁻¹.  

You want to prepare a 0.002 mol·L⁻¹ solution.

1. Moles of Fe(NO₃)₃

\text{Moles of Fe(NO$_{3}$})_{3} = \text{0.5 mL stock} \times \dfrac{\text{0.2 mmol Fe(NO$_{3})$}_{3}}{\text{1 mL stock}}\\\\= \text{0.1 mmol Fe(NO$_{3})$}_{3}

2. Volume of dilute solution

V = \text{0.1 mmoL Fe(NO$_{3})$}_{3}\times \dfrac{\text{1 mL solution}}{\text{0.002 mmoL Fe(NO$_{3})$}_{3}}= \textbf{50 mL solution}

8 0
3 years ago
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