By definition we have to:
LOG (k2 / k1)=(-Ea/R)*(1/T1-1/T2)
Where,
k1 = 0.0117 s-1
K2 = 0.689 s-1
T1 = 400.0 k
T2 = 450.0 k
R is the ideal gas constant
R = 8.314 KJ / (Kmol * K)
Substituting
ln (0.0117/0.689)=-Ea/(8.314)*((1/400)-(1/450))
Clearing Ea:
Ea = 122 kJ
answer
<span> the activation energy in kilojoules for this reaction is
</span> Ea = 122 kJ
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Answer:
x-component of velocity = 5.7 m/s
y-component of velocity = -1.4 m/s
Explanation:
Use first equation of motion to find components of velocity at a given time:
where, 
is the final velocity, 
is the initial velocity, 
is the acceleration and 
is the time.
Given:
Answer:
glucose + oxygen -> carbon dioxide + water + energy
Explanation:
The chemical equation for aerobic respiration is C6H12O6 + 6O2 → 6CO2 + 6H2O (glucose + oxygen -> carbon dioxide + water). It also produces energy.
<span>sometimes you can see yourself as well, due to refraction and reflection
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