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Alexus [3.1K]
3 years ago
8

(5.391 × 10−7) + (2.5531 × 10−6)

Chemistry
2 answers:
Alexeev081 [22]3 years ago
6 0

Answer:

66.441

I hope this helps!

Helen [10]3 years ago
6 0

Answer:

66.441

Explanation:

(5.391 × 10-7) + (2.5531 × 10-6)

(46.91) + (19.531)

66.441

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Which of the following atoms would have a charge of +1?
erica [24]

Answer: An atom with 6 protons, 5 electrons, and 7 neutrons

Explanation: In this case, neutrons do not matter as they have a charge of 0, or no charge. A proton has a charge of +1 and an electron has a charge of -1. Since there are 6 protons, the total charge of the protons would be +6. Since there are 5 electrons the total charge of the electrons would be -5. +6 - 5 would result in a charge of +1. This means that this atom would have an overall charge of + 1. Basically, if there is one more proton than electron, then the overall charge of the atom will be +1 but if there is one more electron than proton, then the overall charge of the atom will be -1.

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3 years ago
What is the volume of a sample of ammonia gas (NH3) if it contains 0.23 moles?​
LekaFEV [45]

The volume of a sample of ammonia gas : 5.152 L

<h3>Further explanation</h3>

Given

0.23 moles of ammonia

Required

The volume of a sample

Solution

Assumed on STP

Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). At STP, Vm is 22.4 liters / mol.

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= 0.23 x 22.4 L

= 5.152 L

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3 years ago
What are fluids? Why are they so called?​
navik [9.2K]

Answer:

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8 0
3 years ago
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3 years ago
Your apple juice has a molarity of 3.4 M and a volume of 0.895 litres. What does a student have to do to decrease the molarity t
Jlenok [28]

Answer:

4.285 L of water must be added.

Explanation:

Hello there!

In this case, for this dilution-like problems, we need to figure out the final volume of the resulting solution so that we would be able to obtain the correct volume of diluent (water) to be added. In such a way, we can obtain the final volume, V2, as shown below:

M_1V_1=M_2V_2\\\\V_2=\frac{M_1V_1}{M_2}

Thus, by plugging in the initial molarity, initial volume and final molarity (0.587 M) we obtain:

V_2=\frac{3.4M*0.895 L}{0.587M}\\\\V_2=5.18L

It means we need to add:

V_{H_2O} ^{added}=5.18L-0.895L=4.285L

Of diluent water.

Regards!

6 0
3 years ago
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