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3 years ago

(5.391 × 10−7) + (2.5531 × 10−6)

Chemistry

2 answers:

Alexeev081 [22]3 years ago

6 0

Answer:

66.441

I hope this helps!

Helen [10]3 years ago

6 0

Answer:

66.441

Explanation:

(5.391 × 10-7) + (2.5531 × 10-6)

(46.91) + (19.531)

66.441

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Р<br> +<br> 02<br> =<br> P4O6 <br> balance the equation

sergejj [24]

To balance a chemical equation, both sides should have equal mass, or in other words both sides should have same number of atoms as to follow the conservation of mass rule.

P + O₂ = P₄O₆

LHS:

Number of Phosphorus atoms = 1 atom

Number of Oxygen atoms = 2 atoms

RHS:

Number of Phosphorous atoms = 4 atoms

Number of Oxygen atoms = 6 atoms

Also since P₄O₆ has the most number of atoms we will make the LHS equalize to P₄O₆.

Difference between Phosphorous atoms in LHS to RHS = 3

Since phosphorous is a monatomic we need 3 phosphorous atoms extra

Difference between Oxygen atoms is LHS to RHS = 4

But Oxygen is diatomic, so we need 4/2 = 2 Oxygen molecules

Now lets see if it is balanced

P + 3P + O₂ + 2O₂ -------> P₄O₆

4P + 3O₂ ------> P₄O₆

LHS:

Phosphorous atoms = 4 atoms

Oxygen atoms = 3 × 2 = 6 atoms

RHS:

Phosphorous atoms = 4 atoms

Oxygen atoms = 6 atoms

LHS = RHS

Therefore the balanced equation is 4P + 3O₂ = P₄O₆

Happy to help :)

If you need more explanation or help in any other question, feel free to ask

3 0

3 years ago

Determine the kinetic energy of an 833.0 kg roller coaster car moving at a speed of 20.0 m/s

trasher [3.6K]

Answer:

166,600J

Explanation:

Kinetic energy (K.E), which is the energy due to motion of a body, can be calculated by using the formula;

K.E = 1/2 × m × v²

Where;

K.E = kinetic energy (joules)

m = mass of body (kg)

v = speed or velocity (m/s)

According to this question, the mass of the roller coaster is 833.0 kg while its velocity/speed is 20.0m/s.

K.E = 1/2 × 833 × 20²

K.E = 1/2 × 833 × 400

K.E = 1/2 × 333200

K.E = 166,600

Therefore, the kinetic energy of the roller coaster car is 166,600J.

6 0

3 years ago

A car with a mass of 3700kg. accelerates at a rate of 8.0 m/s^2 in the backward direction. What is the net force acting on the c

Digiron [165]

Answer:

300

Explanation:

bcuz why not

6 0

4 years ago

Suppose you have a 0.10 M solution of AlBr3. What is the concentration of each ion? A. 0.10 M Al3+ ions and 0.30 M Br- ions B. 0

podryga [215]

<u>Answer:</u> The concentration of $Al^{3+}$ ions is 0.10 M and that of $Br^-$ ions is 0.30 M

<u>Explanation:</u>

We are given:

Concentration of $AlBr_3$ = 0.10 M

The chemical equation for the ionization of aluminium bromide follows:

$AlBr_3\rightarrow Al^{3+}+3Br^-$

1 mole of aluminium bromide produces 1 mole of aluminium ions and 3 moles of bromide ions

So, concentration of aluminium ions = 0.10 M

Concentration of bromide ions = $[(3\times 0.1)]=0.3M$

Hence, the concentration of $Al^{3+}$ ions is 0.10 M and that of $Br^-$ ions is 0.30 M

8 0

3 years ago

Consider the following precipitation reaction: Pb(NO3)2(aq) + 2KI(aq) → PbI2(s) + 2KNO3(aq). Which ions are spectator ions? pls

Marta_Voda [28]

Potassium and Nitrate ions are spectator ions in the reaction:

$Pb(NO_3)_2(aq) + 2KI(aq)$ → $PbI_2(s) + 2KNO_3(aq).$

<h3>What are spectator ions?</h3>

Ions that are not involved in the actual chemical reaction are called spectator ions.

A precipitation reaction occurs when two ionic compounds react to produce a precipitate and an insoluble substance which stays in the solution as a spectator ion.

Hence, Potassium and Nitrate ions are spectator ions in the reaction:

$Pb(NO_3)_2(aq) + 2KI(aq)$ → $PbI_2(s) + 2KNO_3(aq).$

Learn more about the spectator ions here:

brainly.com/question/14050476

#SPJ1

6 0

2 years ago