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stepan [7]
3 years ago
11

To what volume should you dilute 55 mL of 12 M stock HNO3 solution to obtain a 0.145 HNO3 solution?

Chemistry
1 answer:
velikii [3]3 years ago
7 0

Answer:

4552 mL

Explanation:

From the question given above, the following data were obtained:

Volume of stock solution (V₁) = 55 mL

Molarity of stock solution (M₁) = 12 M

Molarity of diluted solution (M₂) = 0.145 M

Volume of diluted solution (V₂) =?

The volume of the diluted solution can be obtained by using the dilution formula as illustrated below:

M₁V₁ = M₂V₂

12 × 55 = 0.145 × V₂

660 = 0.145 × V₂

Divide both side by 0.145

V₂ = 660 / 0.145

V₂ ≈ 4552 mL

Thus, the volume of the diluted solution is 4552 mL

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Macroscopic domain: Boiling point elevation, Henry's law, molarity, osmosis.

Microscopic domain: Hydrogen bond, ion-dipole attraction, nonelectrolyte, solvated ion.

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Ion-dipole attraction: It's also an interaction that happens between an ion and a polar compound, so it's part of the microscopic domain.

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