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ohaa [14]
3 years ago
13

Consider a solution consisting of the following two buffer systems:

Chemistry
1 answer:
vazorg [7]3 years ago
7 0

Answer:

Option (e) is correct

Explanation:

According to Henderson - hasel balch equation

For H₂CO₃ / HCO₃⁻

pH = pka + log\frac{[HCO^-_3]}{[H_2CO_3]} \\\\= 6.4 + log\frac{[HCO^-_3]}{[H_2CO_3]} -------(1)

For H₂PO₄⁻ / HPO₄²⁻

pH = pka + log\frac{[HPO_4^2^-]}{[H_2PO_4^-]} \\\\= 7.2 +  log\frac{[HPO_4^2^-]}{[H_2PO_4^-]}-----(2)

Now ph for buffer mixture is 6.4

pH = 6.4 in eqn(1) [HCO₃⁻]- [H₂CO₃]

pH = 6.4 in eqn(2) [H₂PO₄⁻] > [HPO₄²⁻]

Option (e) is correct

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