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2 years ago

Question, if 1 = 10, 2 = 12, 3 = 14, and 4 = 16, what would 5 equal?

Mathematics

2 answers:

zvonat [6]2 years ago

7 0

Answer:

Step-by-step explanation:

It seems like for this pattern, as the x-value(base value) increases, the corresponding y-value(value changing with the base value) increases by 2 given that the function starts with a y-intercept of 8. So at the value 0, the corresponding number would be 8. So in this case, by creating a function regrading this information we can solve for the corresoponding value of 5: y = 2x + 8

y = 2 * 5 + 8

y = 10 + 8

y = 18

5 = 18

Another way to approach this is just by following the pattern given to us in the description. We see that the pattern starts at 10, and increases by 2 for each increasing base value. Therefore, if 4 = 16, then 16 + 2 = 5, so 5 = 18.

DedPeter [7]2 years ago

6 0

Answer:

5=18

Step-by-step explanation:

they are counting by 2s 10,12,14,16,18

Hope this helps!

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Answer:

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Step-by-step explanation:

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lora16 [44]

Answer:

b) 24

Step-by-step explanation:

We solve building the Venn's diagram of these sets.

We have that n(S) is the number of succesful students in a classroom.

n(F) is the number of freshmen student in that classroom.

We have that:

$n(S) = n(s) + n(S \cap F)$

In which n(s) are those who are succeful but not freshmen and $n(S \cap F)$ are those who are succesful and freshmen.

By the same logic, we also have that:

$n(F) = n(f) + n(S \cap F)$

The union is:

$n(S \cup F) = n(s) + n(f) + n(S \cap F)$

In which

$n(S \cup F) = 58$

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$n(f) = n(F) - n(S \cap F) = 28 - n(S \cap F)$

$n(S \cup F) = n(s) + n(f) + n(S \cap F)$

$58 = 54 - n(S \cap F) + 28 - n(S \cap F) + n(S \cap F)$

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So the correct answer is:

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3 years ago

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rewona [7]

Answer:

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