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loris [4]
3 years ago
9

The parking brake on a 1000 kg Cadillac has failed, and it is rolling slowly, at 1 mph , toward a group of small children. Seein

g the situation, you realize you have just enough time to drive your 2000 kg Volkswagen head-on into the Cadillac and save the children.
Physics
1 answer:
GalinKa [24]3 years ago
6 0
Um of momenta = 0( Since both the cars stop) 
<span>Let m1 be the mass of the cadillac and m2 be the mass of the volkswagen. </span>
<span>then, v1=speed of cadillac and v2=speed of volkswagen. </span>
<span>Therefore, (m1)*(v1) + (m2)*(v2) = 0 </span>
<span>Substituting, </span>
<span>(1000*4) + (2000*v2) = 0 </span>
<span>4000 = - 2000 v2 </span>
<span>Therefore, v2= - 2 m/s. </span>
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Point charges of 21.0 μC and 47.0 μC are placed 0.500 m apart. (a) At what point (in m) along the line connecting them is the el
rewona [7]

Answer:

a) x = 0.200 m

b)E = 3.84*10^{-4} N/C

Explanation:

q_1 = 21.0\mu C

q_1 = 47.0\mu C

DISTANCE BETWEEN BOTH POINT CHARGE = 0.5 m

by relation for electric field we have following relation

E = \frac{kq}{x}^2

according to question E = 0

FROM FIGURE

x is the distance from left point charge where electric field is zero

\frac{k21}{x}^2 = \frac{k47}{0.5-x}^2

solving for x we get

\frac{0.5}{x} = 1+ \sqrt{\frac{47}{21}}

x = 0.200 m

b)electric field at half way mean x =0.25

E =\frac{k*21*10^{-6}}{0.25^2} -\frac{k*47*10^{-6}}{0.25^2}

E = 3.84*10^{-4} N/C

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