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loris [4]
3 years ago
9

The parking brake on a 1000 kg Cadillac has failed, and it is rolling slowly, at 1 mph , toward a group of small children. Seein

g the situation, you realize you have just enough time to drive your 2000 kg Volkswagen head-on into the Cadillac and save the children.
Physics
1 answer:
GalinKa [24]3 years ago
6 0
Um of momenta = 0( Since both the cars stop) 
<span>Let m1 be the mass of the cadillac and m2 be the mass of the volkswagen. </span>
<span>then, v1=speed of cadillac and v2=speed of volkswagen. </span>
<span>Therefore, (m1)*(v1) + (m2)*(v2) = 0 </span>
<span>Substituting, </span>
<span>(1000*4) + (2000*v2) = 0 </span>
<span>4000 = - 2000 v2 </span>
<span>Therefore, v2= - 2 m/s. </span>
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A 89.3 kg horizontal circular platform rotates freely with no friction about its center at an initial angular velocity of 1.77 r
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Answer:

\omega_{2} = 1.107\,\frac{rad}{s}

Explanation:

Let assume that circular platform is a solid cylinder. Given the absence of external forces, the situation can be analyzed by applying the Principle of Angular Momentum, which states that:

I_{1}\cdot \omega_{1} = I_{2}\cdot \omega_{2}

The initial moment of inertia is:

I_{1} = \frac{1}{2}\cdot (89.3\,kg)\cdot (1.69\,m)^{2}

I_{1} = 127.525\,kg\cdot m^{2}

Likewise, the final moment of inertia is:

I_{2} = 127.525\,kg\cdot m^{2} + (8.83\,kg)\cdot (1.352\,m)^{2} + (21.1\,kg)\cdot (1.69\,m)^{2}

I_{2} = 203.929\,kg\cdot m^{2}

The final angular speed is:

\omega_{2} = \frac{I_{1}}{I_{2}} \cdot \omega_{1}

\omega_{2} = \frac{127.525\,kg\cdot m^{2}}{203.929\,kg\cdot m^{2}} \cdot (1.77\,\frac{rad}{s} )

\omega_{2} = 1.107\,\frac{rad}{s}

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A firecracker is thrown downward from a height of 2.75m above the ground, with a speed of 3.15m/s. Ignore air resistance, determ
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Here in this question as we can see there is no air friction so we can use the principle of energy conservation

PE_i + KE_i = PE_f + KE_f

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now here we know that

h_1 = 2.75 m

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now plug in all values in above equation

mg*2.75 + 0 = mgh + \frac{1}{2}m(5.23)^2

divide whole equation by mass "m"

9.8*2.75 = 9.8*h + \frac{1}{2}*27.35

9.8*h = 13.27

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