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solniwko [45]
3 years ago
15

Explain about ohm's law.​

Physics
2 answers:
belka [17]3 years ago
4 0

Answer:

Statement:

The electric current passing through a conductor is directly proportional to the potential difference across its ends provided temperature and other physical conditions remain constant.

Explanation:

Current is directly proportional to voltage loss through a resistor. That is, if the current doubles, then so does the voltage. To make a current flow through a resistance there must be a voltage across that resistance. Ohm's Law shows the relationship between the voltage (V), current (I) and resistance (R).

V∝I or I∝V⇒V=IR.

Anastaziya [24]3 years ago
4 0

Explanation:

Ohm's law states that the current through a conductor is proportional to the voltage across the conductor. This is true for many materials (including metals) provided the temperature (and other physical factors) remain constant. The constant of proportionality, R,R is the resistance and the unit is the ohm, with symbol \Omega,Ω. The relationship can be written as:

V, equals, I, R.

V=IR

where V,V is the voltage across the conductor and I,I is the current flowing through it. If a component is ohmic (it obeys Ohm's Law), then its resistance must be independent of current and voltage.

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3 years ago
In a thin film experiment, a wedge of air is used between two glass plates. If the wavelength of the incident light in air is 48
cluponka [151]

Answer:

The thickness is  \Delta y =  2.4 *10^{-6} \  m

Explanation:

From the question we are told that

   The wavelength is  \lambda  = 480 \ nm = 480*10^{-9} \  m

    The first order of the dark  fringe is  m_1 =  16

     The second order of dark fringe considered is  m_2 = 6

Generally the condition for destructive interference is mathematically represented as

        y = \frac{m \lambda}{2}

Here y is the path difference between the central maxima(i.e the origin) and any dark fringe

So  the path difference between the 16th dark fringe and the 6th dark fringe is mathematically represented as

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=>  y_1 - y_2 = \Delta y =  \frac{16 *480*10^{-9}}{2} -  \frac{6 *480*10^{-9}}{2}

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8 0
3 years ago
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