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Katyanochek1 [597]
2 years ago
11

L 6.3.2 Test (CST):

Chemistry
1 answer:
dalvyx [7]2 years ago
5 0

B. Water Temperature {A PE X}

Explanation:

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Which option supports a theory and allows it to remain the same
mr_godi [17]

Answer:

D.

Explanation:

That would be the last option.

Repeated similar experimental outcomes are confirmation of the theory.

4 0
3 years ago
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In the reaction between copper and silver nitrate, 95.3 g of silver and 82.9g of copper nitrate are produced. How much of each r
Nastasia [14]

Reaction

2AgNO₃  +  Cu ⇒ Cu(NO₃)₂  +  2Ag

mol silver (Ag): 95.3 : 108 g/mol = 0.882

mol  copper nitrate (Cu(NO₃)₂): 82.9 : 187.5 g/mol = 0.441

mol Ag = 2 x mol Cu(NO₃)₂, so 0.441 being the mole basis of the reactants

mol Cu = 0.441

mass Cu = 0.441 x 63.5 g/mol = 28 g

mol AgNO₃ = 0.882

mass AgNO₃ = 0.882 x 170 g/mol = 149.94 g

5 0
3 years ago
What quantity of energy would be necessary to boil water with a mass of
anygoal [31]

Answer:

i think 554 I think

Explanation:

maybe ..

6 0
3 years ago
A shockwave of energy nearby can cause a molecular cloud to collapse under its own _________________.
goblinko [34]

Answer:

Stars form in cold, dense regions of space called molecular clouds. When the force of gravity pulling in on the cloud is greater than the strength of internal pressure pushing out, the cloud collapses into a protostar.

Explanation:

Hope it helps

7 0
3 years ago
Which equation demonstrates that nuclear fusion forms elements that are heavier than helium
yan [13]

Answer: The correct option is, 2.

Explanation:

Nuclear fission: It is defined as the reactions in which a larger unstable nuclei breaks into two or more smaller stable nuclei.

Nuclear fusion: It is defined as the reaction where two smaller nuclei combine together to form a larger nuclei.

Option 1 & option 2 shows fusion reaction and option 3 & option 4 shows fission reaction.

In option 1, helium itself is forming but in option 2, element is heavier than forming which is, neon.

Hence, the correct option is 2.

6 0
4 years ago
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