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3 years ago

1. What is the pressure, in atmospheres, exerted by a 0.500 mol sample

Chemistry

1 answer:

Vadim26 [7]3 years ago

8 0

Answer:

0.102 atmospheres

Explanation:

PV=nRT

P=nRT/V

P=0.5*0.082057*25/10=0.102 atmospheres

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For single bonds between similar types of atoms, how does the strength of the bond relate to the sizes of the atoms? Explain.

uysha [10]

When comparing single bonds between atoms of comparable types, the stronger the bond is, the bigger the atom, the weaker it is.

The length of the X-H bond lengthens while the strength of the bond shortens with increasing halogen size (F-H strongest, I-H weakest). When comparing single bonds between atoms of similar sorts, the larger the atom, the weaker the bond. It can be explained by the fact that less energy is required to break the bond the bigger the atom's atomic size. The force of attraction from the nucleus to the outermost orbit will be less for iodine since it has a larger atom than the other elements in the group.

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1 year ago

A scientist did an investigation on the growth of koi fish. He selected forty newly hatched koi from the same clutch of eggs. He

Luda [366]

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4 years ago

A tire at 21°C has a pressure of 0.82 atm. Its temperature decreases to –3.5°C. If there is no volume change in the tire, what i

Shtirlitz [24]

Answer:

Explanation:

0.75

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3 years ago

Find the mass in grams of 3.00 x 1023 molecules of F2

LUCKY_DIMON [66]

<h3>Answer:</h3>

18.9 g F₂

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

Reading a Periodic Table
Using Dimensional Analysis
Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<h3>Explanation:</h3>

<u>Step 1: Define</u>

3.00 × 10²³ molecules F₂

<u>Step 2: Identify Conversions</u>

Avogadro's Number

Molar Mass of F₂ (Diatomic) - 38.00 g/mol

<u>Step 3: Convert</u>

Set up: $\displaystyle 3.00 \cdot 10^{23} \ molecules \ F_2(\frac{1 \ mol \ F_2}{6.022 \cdot 10^{23} \ molecules \ F_2})(\frac{38.00 \ g \ F_2}{1 \ mol F_2})$
Multiply: $\displaystyle 18.9306 \ g \ F_2$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

18.9306 g F₂ ≈ 18.9 g F₂

8 0

3 years ago

How many grams of NO can be produced from the following reaction if 68.2 grams of NO2 is consumed?

Semenov [28]

Answer:

Option 4. 14.8 g

Explanation:

3NO2 + H2O → 2HNO3 + NO

First let us calculate the molar mass of NO2 and NO. This is illustrated below;

Molar Mass of NO2 = 14 + (2x16) = 14 + 32 = 46g/mol

Mass of NO2 from the question = 3 x 46 = 138g.

Molar Mass of NO = 14 +16 = 30g/mol

From the equation,

138g of NO2 reacted to produce 30g of NO

Therefore, 68.2g of NO2 will react to produce = (68.2 x 30)/138 = 14.8g of NO.

3 0

3 years ago