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2 years ago

Is the chemical equation balanced? Yes or no

Chemistry

2 answers:

Strike441 [17]2 years ago

6 0

I think it is not so no

irinina [24]2 years ago

5 0

Answer:

Yes the equation is balanced 

Explanation:

There is 2Na and 2F on both sides which means LHS=RHS. Hence,its balanced.

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The atomic number of fluorine is 9. How many electrons does an ion of fluorine have if it is represented by the symbol shown bel

Irina-Kira [14]

See charge on ion is -1 .

Hence it has taken 1 electron

Now first look at EC of Fluorine(F)

$\\ \bull\sf\dashrightarrow 1s^22s^22p^5$

Now one electron added .hence no of electrons is 10now

Look at the EC

$\\ \bull\sf\dashrightarrow 1s^22s^22p^6$

$\\ \bull\sf\dashrightarrow [He]$

Option C is correct.

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2 years ago

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You are at home in your air conditioned garage. You are planning a family road trip from New York to Florida. You are lnfating t

Ksenya-84 [330]

Hello!

According to the Charles' Law, the volume of a gas is proportional to temperature when pressure is constant. When going from New York to Florida, if the pressure is left constant the volume of the tires will increase.

The final volume of the tires can be calculated from the following equation, derived from Charles' Law:

$V2= \frac{V1}{T1}*T2=\frac{10 L}{10degC}*32degC=32 L$

Have a nice day!

3 0

3 years ago

Why is creativity important in science?

nasty-shy [4]

Because you need to know how/ learn to try new things for (new experiments) and creativity will teach you different ways on how to do it.

4 0

3 years ago

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Determine the vapor pressure (atm) of rubbing alcohol (isopropanol) at 20.0 °C. The normal boiling point of isopropanol is 82.3

jeyben [28]

Here we apply the Clausius-Clapeyron equation:
ln(P₁/P₂) = ΔH/R x (1/T₂ - 1/T₁)

The normal vapor pressure is 4.24 kPa (P₁)
The boiling point at this pressure is 293 K (P₂)
The heat of vaporization is 39.9 kJ/mol (ΔH)
We need to find the vapor pressure (P₂) at the given temperature 355.3 K (T₂)

ln(4.24/P₂) = 39.9/0.008314 x (1/355.3 - 1/293)
P₂ = 101.2 kPa

8 0

3 years ago

A sample that contains only SrCO3 and BaCO3 weighs 0.846 g. When it is dissolved in excess acid, 0.234 g carbon dioxide is liber

In-s [12.5K]

Answer:28.605

Explanation:First, the molar mass of of SrCO3, BaCO3 and CO2 has to be calculated, (using the molar mass of each element Sr = 87.62, Ba = 137.327, C=12.011, O= 16.00)

The molar masses are;

SrCO3 = 87.62 + 12.011 + (3*16) = 147.631g/mol

BaCO3 = 79.904 + 12.011 + (3*16) = 197.34 g/mol

CO2 = 12.011 + (2*16) = 44.011 g/mol

To obtain one of the equations to solve the problem;

The sample is made of SrCO3 and BaCO3 and has a mass of 0.846 g. Representing the mass of SrCO3 as ma and that of BaCO3 as mb. The first equation can be written as:

ma + mb = 0.846g (1)

To obtain another equation in order to be able to determine the different percentages of the compounds (SrCO3 and BaCO3) that make of the sample, a relationship can be obtained by determining the relationship between the number of moles of CO2 formed as the mass of the SrCO3 and BaCO3;

The number of moles of CO2 formed = (mass of CO2)/(molar mass) =0.234/44.011 =0.00532moles

CO2 contains 1 mole of carbon (C) so therefore 0.00532 moles of CO2 contains 0.00532 moles of C

The sample produced 0.00532 moles of CO2, therefore the number of moles SrCO3 and BaCO3 that produced this amount can be calculated using the formula;

= (mass )/(molar mass)

No of moles of SrCO3 and BaCO3 will be ma/147.631 and mb/197.34 moles respectively

The total amount of C molecules produced by SrCO3 and BaCO3 will be 0.00532 moles of C

The second equation can be written as

ma/147.631 + mb/197.34= 0.00532 (2)

Solving Equation (1) and (2) simultaneously;

ma = 0.604g; mb = 0.242g

Therefore the percentage of BaCO3 = (mass of BaCO3 )/(mass of sample )*100

= 0.242/(0.846 )*100

= 28.605%

5 0

3 years ago