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mixas84 [53]
2 years ago
15

Is the chemical equation balanced? Yes or no

Chemistry
2 answers:
Strike441 [17]2 years ago
6 0
I think it is not so no
irinina [24]2 years ago
5 0

Answer:

<em><u>Yes the equation is balanced </u></em>

Explanation:

<em>There</em><em> </em><em>is</em><em> </em><em>2Na</em><em> </em><em>and</em><em> </em><em>2F</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em><em> </em><em>which</em><em> </em><em>means</em><em> </em><em>LHS</em><em>=</em><em>RHS</em><em>.</em><em> </em><em>Hence</em><em>,</em><em>its</em><em> </em><em>balanced</em><em>.</em><em> </em>

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Percent Composition and Determining Empirical And Molecular Formulas
raketka [301]

Answer:

% comp. H = 2.8%, % comp. Cl = 97.2%

Explanation:

HCl mass = mass of H + mass of Cl

HCL mass = 1.00794 + 35.453 = 36.46094

% comp. of H = 1.007694 / 36.46094 x 100 = around 2.8% (2.76376308455)

% comp. of Cl = 35.453 / 36.46094 x 100 = around 97.2% (97.2355622208)

3 0
2 years ago
The amplitude of a wave tells you how fast the wave is moving. True False
pshichka [43]
The answer is False. the amplitude shows how high or low something is
6 0
2 years ago
a technician mixes 80 ml of a 5% solution with 10 ml of water. what is the final percentage strength of the solution prepared?
Vinvika [58]

A technician mixes 80 ml of a 5% solution with 10 ml of water.  the final percentage strength of the solution prepared is 40 %.

given that :

8 ml of a 5 % solution mix with 10 ml . that means the 80 mL of 5 % solution is diluted with water of 10 mL

therefore, 80 × 5 = 10 × x %

x % = 40 %

Therefore, the final percentage strength of the solution is 40 %

Thus, A technician mixes 80 ml of a 5% solution with 10 ml of water.  the final percentage strength of the solution prepared is 40 %.

To learn more about percentage strength here

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5 0
1 year ago
State whether homgenous mixture or heterogenoues mixture soda water
Citrus2011 [14]

Answer: homogeneous

Explanation: The taste of soda water is constant till the end. The carbon dioxide is dissolved homogeneously in soda water.

4 0
3 years ago
Determine the type of alcohol corresponding to each given description or name. 1-pentanol 3-ethyl-3-pentanol 2-hexanol An alcoho
pochemuha

Answer:

1). 1-pentanol - <u>Primary</u>

2). 3-ethyl-3-pentanol - <u>Tertiary</u>

3). 2-hexanol - <u>Secondary</u>

4). Alcohol with two other carbons attached to the carbon with the hydroxyl group - <u>Secondary</u>

5). Alcohol with one other carbon attached to the carbon with the hydroxyl group - <u>Primary</u>

6). Alcohol with three other carbons attached to the carbon with the hydroxyl group - <u>Tertiary</u>

Explanation:

The distinct types of alcohol have been matched with the categories above as per their descriptions provided. In chemistry, alcohols have been categorized into three different categories namely primary, secondary, and tertiary.

In the primary type, those alcohols are involved in which there is an association of hydroxyl group to a primary atom of carbon along with a minimum of two atoms of hydrogen. Example; ethanol.

In the secondary type, the alcohols have an association of carbon atoms to hydroxyl with a single atom of hydrogen and has a formula of '-CHROH.' Example: 2 - propanol.

In the tertiary alcohols, here the association is between the hydroxyl group with the carbon atom that is saturated and possessing 3 atoms of carbon associated with it. It has a formula of '-CR2OH.' Example:  3-ethyl-3-pentanol, -tert -butyl alcohol, etc.

7 0
3 years ago
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