The answer is 4! Hope this Helps
Answer : The name of the compounds are,
= Copper(I)iodide
= Iron(III)oxide
= Cobalt(II)fluoride
= Iron(II)oxide
Explanation :
<u>Naming rules for the compounds :</u>
- write the cation name first then name the anion.
- If the cation is the transition metals with various charges, write the charge by using parenthesis and Roman numerals after the metal name.
- For mono-atomic anions, use suffix (-ide).
Answer:
The mass of iron produced is 44.29 grams
Explanation:
Al + FeO3
Aluminium + Iron III oxide
2Al + F₂O₃ → Al₂O₃ + 2Fe
Molar mass of Al = 26.981539 g/mol
Molar mass of F₂O₃ = 159.69 g/mol
Number of moles of Aluminium = 21.4 g/26.981539 g/mol = 0.7931 moles
Number of moles of F₂O₃ = 91.3 g/159.69 g/mol = 0.572 moles
Hence, 1 mole of Al combines with 1/2 moles of F₂O₃, 0.7931 moles of Al will combine with 0.7931 × 1/2 or 0.3966 moles of F₂O₃ to produce 0.7931 moles of iron
Molar mass of iron = 55.845 g/mol
Therefore the mass of iron produced = Number of moles × Molar mass = 0.7931 × 55.845 = 44.29 grams.
Although it's true that MgO is only very slightly soluble in water, you can consider the mixture a conventional solution for the purposes of this question. The % mass is the mass of MgO divided by the mass of the entire solution:
45.8 / (45.8 + 205) * 100 = <span>18.3%</span>