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zubka84 [21]
3 years ago
10

What term is given to a substance that can dissolve in a particular liquid?

Chemistry
1 answer:
Elis [28]3 years ago
3 0

Question options:

1. Insoluble

2. Soluble

3. Solvable

Answer:

Soluble

Explanation:

The solubility is a chemical property referring to the ability of the solute to dissolve in a solvent and form a homogeneous mixture (solution). It is measured in terms of the maximum amount of solute dissolved in a solvent at equilibrium.

<u>Therefore, a substance is soluble in a particular liquid if it is able to dissolve in a solvent.</u>

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How many molecules of ethanol (c2h5oh) (the alcohol in alcoholic beverages) are present in 155 ml of ethanol? the density of eth
ozzi

First convert volume to mass:

mass = 0.789 g/mL * 155 mL = 122.295 g

 

Then convert mass to number of moles:

number of moles = 122.295 g * (1 mole / 46 g) = 2.66 moles

 

Using avogadros number, we get the molecules:

<span>number of molecules = 2.66 moles * 6.022 x 10^23 molecules / mole = 1.6 x 10^24 molecules</span>

4 0
3 years ago
What is the function of an Erlenmeyer flask?
JulijaS [17]
An Erlenmeyer flask is laboratory flask that has a conical shape and flat bottom with a tapered mouth. The Erlenmeyer flask is used for pouring, mixing and storing of chemicals in the laboratory. It was created by Emil Erlenmeyer in the 1860s.
6 0
3 years ago
Melamine, C3N3(NH2)3, is used in adhesives and resins. It is manufactured in a two-step process: CO(NH2)2(l) → HNCO(l) + NH3(g)
svetlana [45]

Answer:

43.13Kg of melamine

Explanation:

The problem gives you the mass of urea and two balanced equations:CO(NH_{2})_{2}_{(l)}=HNCO_{(l)}+NH_{3}_{(g)}

6HNO_{l}=C_{3}N_{3}(NH_{2})_{3}_{(l)}+3CO_{2}_{(g)}

First we need to calculate the number of moles of urea that are used in the reaction, so:

molar mass of urea = 60.06\frac{g}{mol}*\frac{1kg}{1000g}=0.06006\frac{Kg}{mol}

The problem says that you have 161.2Kg of urea, so you take that mass of urea and find the moles of urea:

161.2Kg of urea*\frac{1molofurea}{0.06006Kgofurea}=2684 moles of urea

Now from the stoichiometry you have:

2684 moles of urea*\frac{1molofHNCO}{1molurea}*\frac{1molofmelamine}{6molesofHNCO} = 447 moles of melamine

The molar mass of the melamine is 126.12\frac{g}{mol} so we have:

447molesofmelamine*\frac{126.12g}{1molofmelamine} = 5637.64 g of melamine

Converting that mass of melamine to Kg:

5637.64 g of melamine *\frac{1Kg}{1000g} = 56.38 Kg of melamine, that is the theoretical yield of melamine.

Finally we need to calculate the mass of melamine with a yield of 76.5%, so we have:

%yield = 100*(Actual yield of melamine / Theoretical yield of melamine)

Actual yield of melamine = \frac{76.5}{100}*56.38Kg = 43.13Kg of melamine

8 0
3 years ago
Help this is not that hard I think
Thepotemich [5.8K]

Answer:

1,) True

2.) False

3.) A Moraine

Explanation:

Hope this helps

Please Mark As Brainliest

8 0
3 years ago
A solution in equilibrium with solid barium phosphate (ba3(p o4)2) is found to have a barium ion concentration of 0.0005 m and a
maks197457 [2]
Answer is: <span> 3. 5.2x10−7.
</span>Balanced chemical reaction (dissociation): 
Ba₃(PO₄)₂(s) → 3Ba²⁺(aq) + 2PO₄³⁻(aq).
[Ba²⁺<span>] = 0,0005 M.
</span>Ksp(Ba₃(PO₄)₂) = 3,4·10⁻²³.
Ksp = [Ba²⁺]³ · [PO₄³⁻]².
3,4·10⁻²³ = (0,0005 M)³ · [PO₄³⁻]².
[PO₄³⁻] = √3,4·10⁻²³ ÷ 1,25·10⁻¹⁰.
[PO₄³⁻] = 5,2·10⁻⁷ M.
<span>Ksp is the solubility product constant for a solid substance dissolving in an aqueous solution.
</span>

4 0
3 years ago
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