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Sin(x) = base / hypotenuse
sin(x) = 7/9
x = arcsin(7/9)
x = 51 degrees
8.9
The equation for the grain size is expressed as the equality:
Nm(M/100)^2 = 2^(n-1)
where
Nm = number of grains per square inch at magnification M.
M = Magnification
n = ASTM grain size number
Let's solve for n, then substitute the known values and calculate.
Nm(M/100)^2 = 2^(n-1)
log(Nm(M/100)^2) = log(2^(n-1))
log(Nm) + 2*log(M/100) = (n-1) * log(2)
(log(Nm) + 2*log(M/100))/log(2) = n-1
(log(Nm) + 2*log(M/100))/log(2) + 1 = n
(log(33) + 2*log(270/100))/log(2) + 1 = n
(1.51851394 + 2*0.431363764)/0.301029996 + 1 = n
(1.51851394 + 0.862727528)/0.301029996 + 1 = n
2.381241468/0.301029996 + 1 = n
7.910312934 + 1 = n
8.910312934 = n
So the ASTM grain size number is 8.9
If you want to calculate the number of grains per square inch, you'd use the
same formula with M equal to 1. So:
Nm(M/100)^2 = 2^(n-1)
Nm(1/100)^2 = 2^(8.9-1)
Nm(1/10000) = 2^7.9
Nm(1/10000) = 238.8564458
Nm = 2388564.458
Or about 2,400,000 grains per square inch.
Given:
The height of the cylinder = 12 in
The diameter of the base of the cylinder = 8 in.
To find:
The volume of the cylinder.
Solution:
The diameter of the base of the cylinder is 8 in. The radius is half of its diameter. So,


So, the radius of the base of the cylinder is 4 in.
The height of the cylinder, h = 12 in.
Base area of the cylinder is:

Where, B is the base area and r is the radius.


So, the base area is
square inches.
The volume of the cylinder is:


Where, r is radius, h is height, B is base area.
Putting
and
, we get


So, the volume is
cubic inches.
Therefore,
.