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charle [14.2K]
2 years ago
14

Please help me please

Chemistry
1 answer:
Mademuasel [1]2 years ago
6 0

Answer:

I can help you with that... I cannot screenshot your question... what you can do is send me that PDF

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What is the net charge of the peptide arg-ala-phe-leu at ph 8?
adell [148]
The structure of this oligopeptide is attached:

It consists of arginine - alanine - phenylalanine and leucine

From the picture we can see that N terminus charge is +1
Also Arginine is considered as basic amino acid with charge +1
C terminus charge is -1

At pH = 8, the whose pKa are less than pH will be deprotonated and the net charge will be +1 

So the net charge of this oligopeptide is +1 at pH = 8 

3 0
3 years ago
Why is galvanized steel preferred for outdoor uses?
Marizza181 [45]
<span>Galvanized steel is preferred for outdoor uses because it is ideal to prevent rotting/corrosion A steel will rot more quickly if it's exposed to a larger amount of oxygen and H2O , which will exist if we put it oudoor Coating the steel with additional zinc will slow down the process</span>
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3 years ago
Si la eficiencia de una máquina de calor es del 50% significa que ?
Karolina [17]

Answer:

No toques el link

Explanation:

8 0
3 years ago
PLEASE HELP ASAP PLEASE
USPshnik [31]

Answer:

<em>If it served you, give me 5 stars please, thank you!</em>

<em />

<em>m = </em><u><em>25</em></u><em> </em><em> </em><u><em>Kg</em></u>

8 0
3 years ago
Suppose that on a dry, sunny day when the air temperature is near 37 ∘C,37 ∘C, a certain swimming pool would increase in tempera
ioda

Answer:

The fraction of water body necessary to keep the temperature constant is 0,0051.

Explanation:

Heat:

Q=m*Ce*ΔT

Q= heat  (unknown)

m= mass  (unknown)

Ce= especific heat (1 cal/g*°C)

ΔT= variation of temperature  (2.75 °C)  

Latent heat:

ΔE=∝mΔHvap

ΔE= latent heat

m= mass  (unknown)

∝= mass fraction (unknown)

ΔHvap= enthalpy of vaporization (539.4 cal/g)

Since Q and E are equal, we can match both equations:

m*Ce*ΔT=∝*m*ΔHvap

Mass fraction is:

∝=\frac{Ce*ΔT}{ΔHvap}

∝=\frac{(1 cal/g*°C)*2.75°C}{539.4 cal/g}

∝=0,0051

7 0
3 years ago
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