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faust18 [17]
3 years ago
9

Element X has two natural isotopes. The isotope with a mass of 10.012 amu has a relative abundance of 19.91%. The isotope with a

mass of 11.009 amu has a relative abundance of 80.09%. Calculate the atomic mass of this element
Chemistry
1 answer:
SIZIF [17.4K]3 years ago
4 0
To find the atomic mass, multiply the individual atomic masses with their relative abundances and add them up.

10.012*0.1991 + 11.009*0.8009 = 10.810 amu (5 s.f.)

Element X is Boron.
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Answer:

λ = 4.59 ×10⁻³ nm

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