Answer:
d. Copper (II) sulfate
Explanation:
Given data:
Mass of Al = 1.25 g
Mass of CuSO₄ = 3.28 g
What is limiting reactant = ?
Solution:
Chemical equation:
2Al + 3CuSO₄ → Al₂ (SO₄)₃ + 3Cu
Number of moles of Al:
Number of moles = mass/molar mass
Number of moles = 1.25 g/ 27 g/mol
Number of moles = 0.05 mol
Number of moles of CuSO₄:
Number of moles = mass/molar mass
Number of moles = 3.28 g/ 159.6 g/mol
Number of moles = 0.02 mol
now we will compare the moles of reactant with product.
Al : Al₂ (SO₄)₃
2 : 1
0.05 : 1/2×0.05=0.025 mol
Al : Cu
2 : 3
0.05 : 3/2×0.05 = 0.075 mol
CuSO₄ : Al₂ (SO₄)₃
3 : 1
0.02 : 1/3×0.02=0.007 mol
CuSO₄ : Cu
3 : 3
0.02 : 0.02
Less number of moles of reactants are produced by CuSO₄ thus it will act as limiting reactant.
Your hypothesis is at the biggenning or the end of you summary
Rust is when a metal turns brown-ish red-ish and that tells you that the metal is old and is no longer useful. we don't want it floating in our bodies because it's rusted metal. hope this helped! :)
Answer:
Option 4
Explanation:
Hydrochloric acid is a strong one, that gives protons to medium. It can be dissociated as this:
HCl → H⁺ + Cl⁻
M means Molarity. It is a sort of concentration that indicates the moles of solute in 1L of solution.
M = moles / volume (L)
We can also say M = mmoles / mL of solution
M . mL = mmoles
0.453 M . 62.85mL = 28.5 mmoles
If we divide by 1000 → 28.5 mmol . 1 mol / 1000 mmol = 0.0285
