Answer:
Changes in environment, food source changes and disease?
Explanation:
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Molecules move from areas of high concentration to areas of low concentration.
Mass of Oxygen required : 24 grams
<h3>Further explanation</h3>
Given
3 moles of H
1.5 moles of O
3 moles of H₂O
Required
Mass of O
Solution
Reaction
2H₂ + O₂ ⇒ 2H₂O
Mass of Oxygen for 1.5 moles of O :
= mol x Ar O
= 1.5 moles x 16 g/mol
= 24 grams
Answer:
The new pressure exerted by the He, is 1266.6 Torr
Explanation:
A typical problem of gases where the volume is increased and the moles and T° keeps on constant. This is an indirect proportion because when the volume of the flask is increased, pressue decreases because molecules collide to a lesser extent with the walls of the vessel.
P₁ . V₁ = P₂ . V₂
760 Torr . 5L = P₂ . 3L
P₂ = (760 Torr . 5L) / 3L
P₂ = 1266.6 Torr
The number of shells increase, the energy level their outer shell have decreases as we go down wards,