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OLEGan [10]
3 years ago
5

Witch of the following best describes a gene

Chemistry
2 answers:
stellarik [79]3 years ago
6 0

Answer:

DNA SEQUANCES WITH DNA PROTIENS

Explanation:

Inga [223]3 years ago
3 0

Answer:

DNA sequences with instructions for building proteins.

Please rate or heart if this helps!

You might be interested in
Which of the following graphs correctly represents the relationship between the temperature and the volume of an ideal gas that
Anon25 [30]

Answer:

The graph of the relationship of temperature one volume is a graphical representation of Charles law.

Explanation:

The graph shows the relationship between volume vs temperature plotted at constant pressure for a fixed amount of gas. As can be observed from the graph, the volume increases with an increase in the temperature, and vice versa. Thus, volume is directly proportional to temperature at a constant pressure, which is the statement of Charles's law.

Volume is plotted on the y- axis, and temperature is on x-axis. The graph is a straight line with a positive slope passing the origin. The equation of the line is V = kT, which is the equation of Charles's law. The slope of the line is k. As temperature approaches zero kelvin, volume also approaches zero.

Real gases do not obey Charles's law at low temperatures. As temperature approaches absolute zero (0 K), the real gases start deviating significantly from Charles's law.

4 0
3 years ago
What are the elements in the "dip" of the periodic table called?
pogonyaev

Answer:

Transition metals are the elements

3 0
4 years ago
What are 3 examples of pairs of atoms with polar covalent bonds?​
mezya [45]

Answer:

Water - H2O

Ammonia - NH3

Sulfur dioxide - SO2

Hydrogen sulfide - H2S

Ethanol - C2H6O

Explanation:

Those are some atoms with polar covalent bonds. Hope this helps!!

8 0
3 years ago
CONVERSION QUESTION
dlinn [17]

Answer:

615 μK/ms.

Explanation:

The conversion of 615mK/s to μK/ms can be obtained as follow:

1 mK/s = 10^-3 K/s

Therefore, 615mK/s = 615x10^-3 K/s

1K/s = 10^6 μK/s

Therefore,

615x10^-3 K/s = 615 x 10^-3 x 10^6 μK/s = 615x10^3 μK/s.

1s = 10^3ms

Therefore,

615x10^3 μK/s = 615x10^3 μK/ 10^3ms = 615 μK/ms.

Therefore,

615 mK/s = 615 μK/ms.

8 0
3 years ago
3. Gold-198 decays with a half-life of 2.7 days according to the equation:198Au → 0−1β + 198Cd
Nadya [2.5K]

a. k=0.256/day

b.sample of Au-198 remains after seven days : 1.67 g

<h3>Further explanation</h3>

1. A half-life of 2.7 days⇒t1/2=2.7 days

The half-life can be expressed in a decay constant( λ)

\tt \displaystyle t_ {1/2} = {\dfrac {\ln (2)} {\lambda}}\\\\\lambda(or~k)=\dfrac{0.693}{2.7}=0.256/day

2. We can use formula : (integrated rate law) :

\tt ln[A]=-kt+ln[Ao]\\\\ln(\dfrac{Ao}{A})=kt

Ao=10 g

t=7 days

k=0.256/day

\tt ln(\dfrac{10}{A})=0.256\times 7\\\\ln(\dfrac{10}{A})=1.792\\\\e^{1.792}=\dfrac{10}{A}\\\\6=\dfrac{10}{A}\rightarrow A=1.67~g

8 0
3 years ago
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