The midpoint M of a guitar string is pulled a distance d = 1.7 mm from equilibrium and released. Point M is observed to undergo
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Answer:
a) 29.36 m
b) 2.44 s
c) 2.57 s
d) 25.117 m/s
Explanation:
t = Time taken
u = Initial velocity = 24 m/s
v = Final velocity
s = Displacement
a = Acceleration due to gravity = 9.81 m/s²
b)
Time taken by the ball to reach the highest point is 2.44 seconds
a)
The highest point reached by the ball above its release point is 29.36 m
c) Total height is 3+29.35 = 32.35 m
The ball reaches the ground 2.57 seconds after reaching the highest point
d)
The ball will hit the ground at 25.2117 m/s
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Answer:
vB = 15.4 m/s
Explanation:
Principle of conservation of energy:
Because there is no friction the mechanical energy is conserve
ΔE = 0
ΔE : mechanical energy change (J)
K : Kinetic energy (J)
U: Potential energy (J)
K = (1/2)mv²
U = m*g*h
Where :
m: mass (kg)
v : speed (m/s)
h : hight (m)
Ef - Ei = 0
(K+U)final - (K+U)initial =0
(K+U)final = (K+U)initial
((1/2)mv²+m*g*h)final = ((1/2)mv²+m*g*h)initial , We divided by m both sides of the equation:
((1/2)vB² + g*hB = (1/2 )vA²+ g*hA
(1/2) (vB)² + (9.8)*(14.7) = 0 + (9.8)(26.8 )
(1/2) (vB)² = (9.8)(26.8 ) - (9.8)*(14.7)
(vB)² = (2)(9.8)(26.8 - 14.7)
(vB)² = 237.16
vB = 15.4 m/s : speed of the cart at B