Answer:
−153.1 J / (K mol)
Explanation:
Calculate the standard entropy of reaction at 298 K for the reaction Hg(liq) + Cl2(g) → HgCl2(s) The standard molar entropies of the species at that temperature are: Sºm (Hg,liq) = 76.02 J / (K mol) ; Sºm (Cl2,g) = 223.07 J / (K mol) ; Sºm (HgCl2,s) = 146.0 J / (K mol)
Hg(liq) + Cl2(g) → HgCl2(s)
Given that;
The standard molar entropies of the species at that temperature are:
Sºm (Hg,liq) = 76.02 J / (K mol) ;
Sºm (Cl2,g) = 223.07 J / (K mol) ;
Sºm (HgCl2,s) = 146.0 J / (K mol)
The standard molar entropies of reaction = Sºm[products] - Sºm [ reactants]
= 146.0 J / (K mol) – [76.02 J / (K mol) +223.07 J / (K mol) ]
= -153.09 J / (K mol)
= or -153.1 J / (K mol)
Hence the answer is −153.1 J / (K mol)
Answer:
counter clockwise
Explanation:
Dont all planets in our solar system rotate counterclockwise?
<span>Assume you have 1.00 L (1000 mL) of solution.
d = m / V
m = d x V = 1.23 g/mL x 1000 mL = 1230 g of solution
0.387 mol/L x 1 L = 0.387 mol HCl
0.387 mol HCl x (36.5 g / 1 mol) = 14.1 g HCl
mass of water = 1230 g solution - 14.1 g HCl = 1216 g H2O = 1.216 kg H2O
molality = mol HCl / kg water = 0.387 mol / 1.216 kg = 0.318 mol/kg (or 0.318 molal)</span>
1 Ounce = 28.3495231 Grams
<span>1 Troy Ounce = 31.1034768 Grams</span>
C. On the left side .. what the chemical uses is always on the left and what it produces is always on the right.
