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3 years ago

What is the term for the material being dissolved in a solution?

Chemistry

2 answers:

diamong [38]3 years ago

8 0

Solute is the term used for a substance being dissolved in a solution.

Darya [45]3 years ago

5 0

The answer to this question is a solvent.

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At the ph found in cells (about 7.0) what happens to the amino group on an amino acid

Andrew [12]

This means that the amino acid is neutral due to the pH equals 7

6 0

3 years ago

calculate the number of grams of CH3COONa * 3H2O (sodium acetate tri-hydrate) needed to make 250.0 mL of a CH3COOH (acetic acid)

anastassius [24]

Answer:

10.88 g

Explanation:

We have:

[CH₃COOH] = 0.10 M

pH = 5.25

Ka = 1.80x10⁻⁵

V = 250.0 mL = 0.250 L

$M_{CH_{3}COONa*3H_{2}O} = molar \thinspace mass = 136 g/mol$

The pH of the buffer solution is:

$pH = pKa + log(\frac{[CH_{3}COONa*3H_{2}O]}{[CH_{3}COOH]})$ (1)

By solving equation (1) for [CH₃COONa*3H₂O] we have:

$log [CH_{3}COONa*3H_{2}O] = pH - pKa + log [CH_{3}COOH]$

$log [CH_{3}COONa*3H_{2}O] = 5.25 - (-log(1.80 \cdot 10^{-5})) + log (0.10) = -0.495$

$[CH_{3}COONa*3H_{2}O] = 10^{-0.495} = 0.32 M$

Hence, the mass of the sodium acetate tri-hydrate is:

$m = moles*M = [CH_{3}COONa*3H_{2}O]*V*M = 0.32 mol/L*0.250 L*136 g/mol = 10.88 g$

Therefore, the number of grams of CH₃COONa*3H₂O needed to make an acetic acid/sodium acetate tri-hydrate buffer solution is 10.88 g.

I hope it helps you!

4 0

3 years ago

What is subshell?please help me

melamori03 [73]

Each shell is composed of one or more subshells. The first K shell has one subshell, called ‘1s’; the L shell has two subshells, called ‘2s’ and ‘2p’; the third shell has ‘3s’, ‘3p’, and ‘3d’; and so on. A subshell is the set of states defined by the azimuthal quantum number, l, within a shell. The values l = 0, 1, 2, 3 correspond s, p, d and f subshells, respectively. The maximum number of electrons which can occupy a subshell is given by 2(2l + 1). This gives two electrons in an s subshell, six electrons in a p subshell, ten electrons in a d subshell and fourteen electrons in an f subshell.

3 0

3 years ago

A 0.245-L flask contains 0.467 mol co2 at 159 °c. Caculate the pressure using Van der Walls equation

AlladinOne [14]

Answer:

The right answer is "60.56 atm".

Explanation:

As we know,

Vander wall's equation is:

⇒ $(P+\frac{n^2 a}{v^2} )(v-nb)=nRT$

or,

⇒ $P=\frac{nRT}{(v-nb)}-\frac{n^2 a}{v^2}$

Here,

a = 3.59 L² atm mol⁻²

b = 0.0427 L mol⁻¹

By putting the values in the above equation, we get

⇒ $P=\frac{0.467\times 0.0821\times 432}{0.245-0.467\times 0.0427}$

$=\frac{(0.467)^2\times 3.49}{(0.245)^2}$

$=73.61-13.05$

$=60.56 \ atm$

8 0

3 years ago

Why does a solute depress the freezing point?

Marina86 [1]

When the solvent disrupts the solvents ability to form that crystal lattice and thus need lower temperatures (freezing point depression) than normally expected to form the solid. 

My guess would be: B. The solute disrupts crystals formation by the solvent

5 0

4 years ago

Read 2 more answers