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Kaylis [27]
3 years ago
7

Please help me anything will help

Physics
1 answer:
spin [16.1K]3 years ago
6 0
Your answer is C) The speed of sound is higher in solids than in liquids. 
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A. If a T-Rex runs 20 meters in 4 seconds, what is it’s average speed?
mariarad [96]

5m/s

100m

Explanation:

Average speed is sum of distance distance traveled in a given time by a body.

 Average speed= \frac{total distance covered}{time taken}

Distance = 20m

time = 4s

  Average speed = \frac{20}{4} = 5m/s

For the spaceship;

   Distance covered = speed x time

Speed = 50m/s

time = 2s

 Distance covered = 50 x 2 = 100m

learn more:

Average speed brainly.com/question/5063905

#learnwithBrainly

3 0
3 years ago
if a bus has a mass of 5000 kg and a velocity of 10 m/s, what must the velocity of a 1500 kg can be to have the same momentum
fgiga [73]

Answer:

qeyygrydfguygffsddtggfxccfufdrfff

6 0
3 years ago
The 2.6-kg collar is released from rest at A and slides down the inclined fixed rod in the vertical plane. The coefficient of ki
neonofarm [45]

Answer:

The attached diagram explains the system,

Sum of Fy = 0

N=9.81

N - mgCos60 = 0

F= ukN= (0.53)(9.81) =

F= 5.12 N

So

F.d= 1/2(mv.v) - mgdsin60

-5.12*0.5 = 0.5*v^2 - 2*(9.81)*(0.5*sin60)

(a)  v = 2.436 m/s

For deflection

-F.x = 1/2(mv.v) - mgxsin60 + 1/2 (k*x*x)

by solving for with values of v, m, g, F, k

800x^2 - 11.87 x - 5.938 = 0

by solving the quadratic equation

x = 0.093, -0.079

(b) x = 0.093 m

correct Answer is 0.093m

Explanation:

3 0
3 years ago
Real world System of equations
valina [46]
WhG exactly are you asking question mark
4 0
3 years ago
A car is driving around a banked curve, with the road surface at an angle of 10.0º. If the radius of curvature of the road is 30
IRISSAK [1]

Answer:

maximum speed 56 km/h

Explanation:

To apply Newton's second law to this system we create a reference system with the horizontal x-axis and the Vertical y-axis. In this system, normal is the only force that we must decompose

       sin 10 = Nx / N

      cos 10 = Ny / N

      Ny = N cos 10

     Nx = N sin 10

Let's develop Newton's equations on each axis

X axis

We include the force of friction towards the center of the curve because the high-speed car has to get out of the curve

     Nx + fr = m a

     a = v2 / r

     fr = mu N

     N sin10 + mu N = m v² / r

     N (sin10 + mu) = m v² / r

Y Axis  

     Ny -W = 0

     N cos 10 = mg

Let's solve these two equations,

    (mg / cos 10) (sin 10 + mu) = m v² / r

    g (tan 10 + μ / cos 10) = v² / r

    v² = r g (tan 10 + μ / cos 10)

They ask us for the maximum speed

   v² = 30.0 9.8 (tan 10+ 0.65 / cos 10)

   v² = 294 (0.8364)  

   v = √(245.9)

   v = 15.68 m / s

Let's reduce this to km / h

   v = 15.68 m / s (1 km / 1000m) (3600s / 1h)

   v = 56.45 km / h

This is the maximum speed so you don't skid

7 0
3 years ago
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