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1 answer:
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The mass that must be added is 0.628 kg
Explanation:
The period of a mass-spring system is given by
where
m is the mass
k is the spring constant
For the initial mass-spring system in the problem, we have
m = 0.500 kg
T = 1.36 s
Solving for k, we find the spring constant:
In the second part, we want the period of the same system to be
T = 2.04 s
Therefore, the mass on the spring in this case must be
Therefore, the mass that must be added is
Learn more about period:
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The force of a charge in an electric field is:
In this case we know the electric field is:
and that the charge is that of the electron, then we have:
Therefore, the magnitude of the force is
and in points down.
The weight of the electron is:
Making the quotient between the force we have:
Therefore, the electric force is approximately 1e9 times the weight.