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3 years ago

6

Which statement is true for the hang time of a projectile?

1 answer:

Neporo4naja [7]3 years ago

8 0

The hang time of a projectile can be calculated solely by knowing the vertical component of the velocity of projection.

This is because all projectiles with the same vertical component of velocity are in flight for the same time.This is possible only if we are able to find the vertical component of velocity and the flight time with the given information.

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If you have two objects on the edge of a cliff, how can you determine which one has the most potential energy?

True [87]

Answer: now take this with a grain of salt because I'm in middle school but I think that the more massive object has more potential energy.

Explanation:

5 0

3 years ago

Frank has a sample of steel that has a mass of 80 grams if the density is 8g/cm3 what is the volume

nikklg [1K]

Density is mass divided by volume. rho=m/v. So, v=m/rho. In frank's case this is 80/8 = 10 cm^3.

7 0

3 years ago

Which substance is a greenhouse gas that is emitted by human activities, is the most widespread, and remains in the air the long

e-lub [12.9K]

Answer:

I am not really sure, but it is probably Carbon Dioxide

Explanation:

3 0

3 years ago

Read 2 more answers

The potential at location A is 382 V. A positively charged particle is released there from rest and arrives at location B with a

jarptica [38.1K]

Answer: 247.67 V

Explanation:

Given

Potential At A $V_a=382\ V$

Potential at $V_c=785\ V$

when particle starts from A it reaches with velocity $v_b$ at Point while when it starts from C it reaches at point B with velocity $2v_b$

Suppose m is the mass of Particle

Change in Kinetic Energy of particle moving under the Potential From A to B

$q\cdot \left ( V_a-V_b\right )=0.5m\cdot (v_b)^2----1$

Change in Kinetic Energy of particle moving under the Potential From C to B

$q\cdot \left ( V_c-V_b\right )=0.5m\cdot (2v_b)^2-----2$

Divide 1 and 2 we get

$\frac{V_a-V_b}{V_c-V_b}=\frac{v_b^2}{4v_b^2}$

on solving we get

$V_b=\frac{4}{3}\cdot V_a-\frac{1}{3}\cdot V_c$

$V_b=\frac{743}{3}=247.67\ V$

4 0

3 years ago

A gas hot water heater is 65% efficient. The energy output to heat the water is 2.3 kWh.

Art [367]

Answer:

3.5 kWh

1.2 kWh are lost

Explanation:

65=2.3/Ein*100

0.65=2.3/Ein

Ein=2.3/.65

Ein=3.5

3.5-2.3=1.2 kWh

7 0

3 years ago