Question

The dark fringe for m = 0 in a young's double-slit experiment is located at an angle of θ = 15°. What is the angle that locates the dark fringe for m = 1?

Answer 1

Answer:

51°

Explanation:

dark fringe equation = dsinθ = (m + 1/2)λ

sinθ = [(m + 1/2)λ]d

sinθ1 = [(m + 1/2)λ]d

sinθ1/sinθ =  [(m + 1/2)(λ/d)] / [[(m + 1/2)(λ/d)] = [(m + 1/2)] / [(m + 1/2)]

sinθ1 = [(m + 1/2)] / [(m + 1/2)] (sinθ)

sinθ1 = [1+1/2]/[0+1/2] (sin15)

sinθ1 = 3sin15

sinθ1 = 0.77645

θ1 = sin^-1( 0.77645)

θ1 = 50.94° = 51°

Answer 2

The dark fringe for m = 0 in a young's double-slit experiment is located at an angle. The angle that locates the dark fringe for m = 1 is  51°.

What is dark fringe?

When light passes through a slit , it produces a spectrum which can be seen on the screen kept a distance in form of fringes of different intensity. The fringe with intensity zero is called the dark fringe.

Given is the angle θ = 15°

The equation for the dark fringe is

d sinθ = (m + 1/2)λ

For m= 0 and m=1, the ratio of the sines  is

sinθ₁/sinθ₀ = [(m + 1/2)] / [(m + 1/2)]

Rearranging for sinθ₁, we have

sinθ₁ = [(m + 1/2)] / [(m + 1/2)] (sinθ₀)

Substituting the values into the equation and solving for θ₁

sinθ₁ = [1+1/2]/[0+1/2] (sin15)

θ₁ = 51°

Thus, the angle that locates the dark fringe fro m = 1 is 51°.

Learn more about dark fringe.

brainly.com/question/14098517

#SPJ4