Remembering the equation Q=MCdeltaT where
q=is the amount of heat energy
M=mass
C=specific heat
deltaT= change in temperature
Therefore, using the equation we can substitute values and solve for q.
Q= (15 grams) (0.129 J/(gx°C))(85-22)
Q=(15) ((0.129 J/(gx°C)) (63)
Q=121.9 Joules
The energy needed to raise the temperature of 15 grams of gold from 22 degrees Celsius to 85 degrees Celsius is then 121.9 Joules or 122 Joules (if rounded up).
Answer:
<u>Physical Properties</u>
1. Metals are shiny but most non - metals lack this property.
2. Metals are able to deform under compression (malleable) but most non - metals lack this property.
<u>Chemical Properties</u>
<u>1</u><u>.</u><u> </u><u>Metal</u><u>s</u><u> </u><u>are</u><u> </u><u>good</u><u> </u><u>conductors</u><u>of</u><u> </u><u>heat</u><u> </u><u>and</u><u> </u><u>electricity</u><u> </u><u>but</u><u> </u><u>most</u><u> </u><u>non</u><u> </u><u>-</u><u> </u><u>metals</u><u> </u><u>are</u><u> </u><u>insulators</u><u>.</u>
<u>2</u><u>.</u><u> </u><u>Metals</u><u>,</u><u> </u><u>when</u><u> </u><u>exposed</u><u> </u><u>to</u><u> </u><u>water</u><u> </u><u>atmospheric</u><u> </u><u>oxygen</u><u> </u><u>tend</u><u> </u><u>to</u><u> </u><u>rust</u><u> </u><u>but</u><u> </u><u>non</u><u> </u><u>-</u><u> </u><u>metals</u><u> </u><u>lack</u><u> </u><u>this</u><u> </u><u>chemical</u><u> </u><u>property</u>
Give me a thanks I been helped a lot of people and non of them is thanks me.
<span>Gold have a single outer electron. This seems disadvantageous, energy-wise, until you look at the orbitals the electrons are in. The lone electron is in an S-orbital. This orbital is thus half full (since s-orbitals can contain 2 electrons), whereas all the other inner orbitals in silver and gold are filled, and hence exceptionally stable. After a full orbital, the next most stable orbital is a half full one. </span>
Answer:
18.0 g H₂O
Explanation:
To find the mass of water (H₂O), you need to (1) convert grams O₂ to moles O₂ (via the molar mass), then (2) convert moles O₂ to moles H₂O (via mole-to-mole ratio from equation coefficients), and then (3) convert moles H₂O to grams H₂O (via the molar mass). It is important to arrange the conversions in a way that allows for the cancellation of units. The final answer should have 3 sig figs to match the sig figs of the given value.
Molar Mass (O₂): 2(15.998 g/mol)
Molar Mass (O₂): 31.996 g/mol
Molar Mass (H₂O): 2(1.008 g/mol) + 15.998 g/mol
Molar Mass (H₂O): 18.014 g/mol
2 H₂ + 1 O₂ -----> 2 H₂O
16.0 g O₂ 1 mole 2 moles H₂O 18.014 g
--------------- x ---------------- x --------------------- x ----------------- = 18.0 g H₂O
31.996 g 1 mole O₂ 1 mole