1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lorasvet [3.4K]
3 years ago
11

In the compound KHSO4, there is an ionic bond between the

Chemistry
1 answer:
kompoz [17]3 years ago
8 0

the ionic bond would be between the potassium, and hydrogen sulfate.
You might be interested in
What is the pH of a sample with [OH-] = 2.5 x 10-11 M?
sveticcg [70]

Answer:

The pH of the sample is 3,4.

Explanation:

We calculate the pOH from the formula pOH = -log (OH-). We know that for all aqueous solutions: pH + pOH = 14, and from there we clear pH:

pOH= -log (OH-)=10,60

pH + pOH = 14

pH + 10,60 = 14

pH=14 -10,60

<em>pH=3,4</em>

3 0
3 years ago
1. Compare masses: a) 0,4mol CO₂ and 0,6mol H₂O ; b) 0,135mol H₂SO₄ and 0,5mol HCI.
bixtya [17]

Answer:

you can now deduct which one is greater or smaller and by how much.

Explanation:

no of moles= mass/molar mass

1ai) 0.4 = m/ ( 12 + (16*2)

m= 0.4* 44

m= 17.6g

ii) 0.6= m/( 2*1 + 16)

m= 0.6 *18

m= 10.8g

b) 0.135 = m/ ( 2*1 +32 + (16*4)

m= 0.135* 98

m= 13.23g

ii) 0.5= m/ (1+35.5)

m= 0.5*36.5

m= 18.25g

2. Avogadro's Number = 6.02×10²³

1 mol of any element= 6.02×10²³ particles

a) 0.1 mol of H20= (6.02×10²³) * 0.1

= 6.02×10²² molecules

ii) 0.3 mol of CO2= (6.02×10²³) * 0.3

= 1.806 × 10²³ molecules

Ans: 0.3 mol of CO2

bi) 0.25 mol of HCl= (6.02×10²³) * 0.25

= 1.505 × 10²³ molecules

bii) - find the no of moles first:

no of moles= mass/molar mass

n= 3.4g/ 34g →mr of H2S in g=2+32= 34g

n= 0.l mol

- use the Avogadro Number.

0.1 mol of H20= (6.02×10²³) * 0.1

= 6.02×10²² molecules.

biii) here you're given the density, use it to find the mass of acetic acid.

ρ = 1049 g/ml

ρ = m/v, where v=5 ml

1049 = m/ 5

m= ρ*v

m= 1049*5

m= 5245 g

• convert this into moles.

mr of CH3COOH= 12 + 3+ 12+ 16+ 16+ 1

= 60

mr in g = 60g

n= m/mr

n= 5245/ 60

n= 87. 41666...

n= 87.4 moles

•using Avogadro's Number:

87.4 moles of acetic acid=(6.02×10²³)*87.4

= 2.25148* 10²⁵

= 2.25 * 10²⁵ molecules

thus, the ans for this is 5 ml of acetic acid.

7 0
2 years ago
How many moles of solute are contained in 3.0 L of a 1.5 M solution? Helppp pleaseee
Art [367]
4.5 moles! I hope my answer helps
8 0
3 years ago
Most particles would travel____from their source to a screen that lit up<br> when struck.
quester [9]

Answer: in a straight path!

Explanation: hope this helps

5 0
2 years ago
Which of these is not a commonly mined metallic substance?
Sliva [168]

Answer:

C) quartz

Explanation:

Quartz is a common mineral. Also, quartz isn't a metallic substance. I'm hoping that this helps :)

5 0
3 years ago
Other questions:
  • Which element is most important to scientists doing radiometric dating? nitrogen carbon -12 carbon - 14 hydrogen next?
    15·2 answers
  • If 82.3 l of an ideal gas is cooled from 46 degrees calius to -166 what will the volume of the gas become
    6·1 answer
  • What is the product of 3 x 10² kg and 2 x 10-3<br> kg?
    15·1 answer
  • An element has five valence electrons available for bonding.this element is most likely which of the following?
    13·1 answer
  • When seeds germinate, roots grow downward and stems grow upward in response to gravity. This response to gravity is called _____
    5·1 answer
  • The diagram illustrates the water cycle.
    7·2 answers
  • Conservation of mass to balance the following reaction. Na2S+ KI= NaI+ K2S
    9·1 answer
  • What will happen to a salt water fish if placed in freshwater?
    5·1 answer
  • a solution of HCI contains 36 percent HCI,by mass and calculate the mole fraction of HCI in the solution?​
    14·1 answer
  • If a 10.0ml sample of unknown liquid has a mass of 7.553g what is the density of the unknown liquid
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!