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lisabon 2012 [21]
3 years ago
7

CAN SOMEONE PLSSS HELP ME LIKE PLS IM GONNA CRY PLSSSSS BRAINLY15 PONITS PLS

Chemistry
1 answer:
Kitty [74]3 years ago
5 0
If there is chloroplasts it’s a plant
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What qualifications do you need to be a research scientist?
il63 [147K]

Answer:

B and D

Explanation:

6 0
3 years ago
In a nuclear reaction, the energy released is equal to 5.4 x 1015 joules. Calculate the mass lost in this reaction. (1 J = 1 kg
Alexeev081 [22]
I think the answer is A.
3 0
3 years ago
Read 2 more answers
Much like its household namesake, a molecular sieve utilizes differences in what property of substances to separate the componen
nlexa [21]

Answer: B . particle size

Explanation:

Let's begin by explaining that a molecular sieve is a device, whose composition allows the absorbtion of molecules that are small enough to pass through its pores, since it is made up of small pores of a precise and uniform size.

Thus, very small molecules manage to pass through the pores of the sieve, while large ones do not.

So, based on this premise, a molecular sieve separates the substances by their size.

Hence, the correct option is B.

4 0
3 years ago
You carefully weigh out 11.00 g of caco3 powder and add it to 44.55 g of hcl solution. you notice bubbles as a reaction takes pl
Zinaida [17]
The bubbles that were observed after the mixing of the two substances is one of the products of the reaction. It is the carbon dioxide that is produced. To determine the mass of this gas produced, we need to remember the Law of conservation of mass where mass cannot be created or destroyed. With this, we can say that the total mass that goes in a process should be equal to the mass that is goes out of the process no matter what the reaction is. We do as follows:

Mass of reactants = mass of products
11.00 + 44.55 = 51.04 + mass of carbon dioxide
mass of carbon dioxide = 4.51 g
8 0
3 years ago
When 3.00 g of sulfur are combined with 3.00 g of oxygen, 6.00 g of sulfur dioxide (SO2) are formed. What mass of oxygen would b
Drupady [299]
Actually, we can answer the problem even without the first statement. All we have to do is write the reaction for the production of sulfur trioxide.

2 S + 3 O₂ → 2 SO₃

The stoichiometric calculations is as follows:

7 g S * 1 mol/32.06 g S = 0.218 mol S
Moles O₂ needed = 0.218 mol S * 3 mol O₂/2 mol S = 0.3275 mol O₂
Since the molar mas of O₂ is 32 g/mol,
Mass of O₂ needed = 0.3275 mol O₂ * 32 g/mol = 10.48 g O₂
3 0
3 years ago
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