Answer:
6.217 pounds
Explanation:
We are given;
- Density of body fats 0.94 g/mL
- Volume of fats removed = 3.0 L
We are required to determine the mass of fats removed in pounds.
We need to know that;
Density = Mass ÷ volume
1 L = 1000 mL, thus, volume is 3000 mL
Rearranging the formula;
Mass = Density × Volume
= 0.94 g/mL × 3000 mL
= 2,820 g
but, 1 pound = 453.592 g
Therefore;
Mass = 2,820 g ÷ 453.592 g per pound
= 6.217 pounds
Thus, the amount of fats removed is 6.217 pounds
Answer: 40.68 kPa
Explanation:
Given that,
Original volume of gas V1 = 21.7 mL
Original pressure of gas P1 = 98.8 kPa
New volume of gas V2 = 52.7 mL
New pressure of gas P2 = ?
Since pressure and volume are given while temperature is constant, apply the formula for Boyle's law
P1V1 = P2V2
98.8 kPa x 21.7 mL = P2 x 52.7L
2143.96 kPa L = 52.7 L x P2
P2 = 2143.96 kPa L / 52.7 L
P2 = 40.68 kPa
Thus, the new pressure of the gas is 40.68 kPa.
First, it is best to know the chemical formula of pyridine which is C5H5N. To determine the number of carbon atoms present in pyridine, multiply 7.05 mol C5H5N with 5 mol C/ 1 mol C5H5N which then results to 35.35 mol of carbon. Then, multiply the answer to Avogadro's number which is 6.022x10^23 atoms. It is then calculated that the number of carbon atoms in 7.05 moles of pyridine is 2.12x10^25 atoms.
Answer:
5 , I think. sorry if its wrong
