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kondor19780726 [428]
2 years ago
14

How many grams are in 3.45 moles CO2

Chemistry
1 answer:
Mamont248 [21]2 years ago
6 0
<h3>Hello There!!</h3>

<u> To Find:-</u>

Grams Present in 3.45 Moles of Carbon.

<u>We </u><u>Know:</u><u>-</u>

Molecular Mass of Carbon Dioxide= 44.01 grams/mol or 44 grams/mol

\text{Moles} = \frac{\text{Mass}}{\text{Molecular mass}}

\implies 3.45 \text{moles} =  \frac{ \text{Mass}}{44 \text{g/mol}}  \\  \\  \implies \text{Mass} = {44 \text{g/mol}} \times 3.45 \text{moles} \\  \\ \implies \text{Mass} = {44 \text{g/}  \cancel\text{ mol}} \times 3.45  \cancel\text{moles} \\  \\ \implies \text{Mass} = 44 \text{g} \times 3.45 \\  \\  \implies  \text{Mass} =  \red{151.8 \text{g}}

\therefore \text{Mass of 3.45 Moles of Carbon Dioxide is =  \red{151.8g}}

<h3>Hope This Helps!!</h3>
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<span>moles = mass / molar mass </span>
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<span>moles Al needed = 2 x moles Fe2O3 </span>
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<span>mass = molar mass x moles </span>
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<span>= 51 g (2 sig figs) 
</span>
So the <span>mass of Al that will react with 150g of Fe2 O3 is 51 grams.</span>
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