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3 years ago

Please help me do this. Study the scenario.

Physics

1 answer:

dem82 [27]3 years ago

8 0

The mechanical advantage of the lever is 3 and the right option is A.) 3.

<h3>What is mechanical advantage?</h3>

Mechanical advantage can be defined as the ratio of load to effort in a machine.

To calculate the mechanical advantage of the lever, we use the formula below.

Formula

M.A = y/x................ Equation 1

Where:

M.A = mechanical advantage of the lever
y = distance moved by effort (input arm)
x = distance moved by load (output arm)

From the question,

Given:

y = 3 m
x = 1 m

Substitute these values into equation 1

M.A = 3/1
M.A = 3.

Hence, The mechanical advantage of the lever is 3 and the right option is A.) 3.

Learn more about mechanical advantage here: brainly.com/question/19038908

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A time-dependent but otherwise uniform magnetic field of magnitude B0(t) is confined in a cylindrical region of radius 6.5 cm. I

Papessa [141]

Answer:

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Explanation:

From the question we are told that

The radius is $d = 6.5 cm = \frac{6.5}{100} = 0.065 m$

The magnitude of the magnetic field is $B = 5.5 T$

The rate at which it decreases is $\frac{dB}{dt} = 24.5G/s = 24.5*10^{-4} T/s$

The distance from the center of field is $r = 1.5 cm = \frac{1.5}{100} = 0.015m$

According to Faraday's law

$\epsilon = - \frac{d \o}{dt}$

and $\epsilon = \int\limits {E} \, dl$

Where the magnetic flux $\o = B* A$

E is the electric field

dl is a unit length

$\int\limits {E} \, dl = - \frac{d}{dt} (B*A)$

${E} l = - \frac{d}{dt} (B*A)$

Now $l$ is the circumference of the circular loop formed by the magnetic field and it mathematically represented as $l = 2\pi r$

A is the area of the circular loop formed by the magnetic field and it mathematically represented as $A= \pi r^2$

${E} (2 \pi r)= - \pi r^2 \frac{dB}{dt}$

$E = \frac{r}{2} [ - \frac{db}{dt} ]$

Substituting values

$E = \frac{0.015}{2} (24*10^{-4})$

$E = 3.6*10^{-5} V/m$

The negative signify the negative which is counterclockwise

The force acting on the proton is mathematically represented as

$F_p = ma$

Also $F_p = q E$

$ma = qE$

Where m is the mass of the the proton which has a value of $m = 1.67 *10^{-27} kg$

$q = 1.602 *10^{-19} C$

$a =\frac{1.60 *10^{-19} *(3.6 *10^{-5}) }{1.67 *10^{-27}}$

$a = 3.45*10^{3} m/s^2$

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gizmo_the_mogwai [7]

Answer:

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aleksandr82 [10.1K]

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