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Arturiano [62]
3 years ago
6

A rock is thrown off a cliff with a horizontal velocity of 18.3 m/s. Right before it hits the ground, it has a vertical velocity

of -31.3 m/s. What is the magnitude of the rock's overall velocity?
Physics
1 answer:
AleksAgata [21]3 years ago
5 0

Answer: 36.257 m/s

Explanation:

The vertical and horizontal components of a projectiles motion are completely independent of each other. The only thing they share is the amount of time in the air. Because they are independent, the acceleration of gravity cannot affect the horizontal acceleration. This means horizontal acceleration is 0. If the acceleration is 0, this means the velocity does not change horizontally. So the final velocity of the x component is equal to the initial.

Now if you actually imagine these two vectors, it forms a right triangle. So you can use the Pythagorean Theorem to find the resultant vector.

a^2+b^2=c^2\\18.3^2+(-31.3)^2 = c^2\\c = 36.257 m/s

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Answer:

It's A & C

Explanation:

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While i was jogging, i wad able to run 5 miles in thirty minutes. from this information, we can determine my?
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Calculate the recoil speed of a 1.4 kg rifle shooting 0.006 kg bullets with muzzle speed of 800 m/a.3.43 m/s
Angelina_Jolie [31]

Answer:

a) 3.43 m/s

Explanation:

Due to the law of conservation of momentum, the total momentum of the bullet - rifle system must be conserved.

The total momentum before the bullet is shot is zero, because they are both at rest, so:

p_i = 0

Instead the total momentum of the system after the shot is:

p_f = mv+MV

where:

m = 0.006 kg is the mass of the bullet

M = 1.4 kg is the mass of the rifle

v = 800 m/s is the velocity of the bullet

V is the recoil velocity of the rifle

The total momentum is conserved, therefore we can write:

p_i = p_f

Which means:

0=mv+MV

Solving for V, we can find the recoil velocity of the rifle:

V=-\frac{mv}{M}=-\frac{(0.006)(800)}{1.4}=-3.43 m/s

where the negative sign indicates that the velocity is opposite to direction of the bullet: so the recoil speed is

a) 3.43 m/s

5 0
3 years ago
For what angle of incidence at the first mirror will this ray strike the midpoint of the second mirror (which is 28.0 cmcm long)
loris [4]

This question is incomplete, the complete question is;

Two plane mirrors intersect at right angles. A laser beam strikes the first of them at a point 11.5 cm from their point of intersection, as shown in the figure.

For what angle of incidence at the first mirror will this ray strike the midpoint of the second mirror (which is 28.0 cmcm long) after reflecting from the first mirror

Answer: angle of incidence is 39.4°

Explanation:

Given that;

two plain mirrors intersect at right angle (90°)

distance d = 11.5 cm

S = 28.0 cm

Now the angle that the reflection ray males with first the mirror equal theta  (∅)

so

tan∅ = (S/2) / d

tan∅ = (28/2) / 11.5

tan∅ = 14 / 11.5

tan∅ = 1.2173

∅ = tan⁻¹ (1.2173)

∅ = 50.6°

so angle of incidence = 90° - ∅

= 90° - 50.6°

= 39.4°

Therefore angle of incidence is 39.4°

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3 years ago
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Answer:

'A' is the the point on the graph that shows a temperature of 40°C and the time of 25 minutes

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