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fredd [130]
3 years ago
10

A benzene ring has alternating double bonds in a -membered ring. Please help me asap

Chemistry
1 answer:
Lisa [10]3 years ago
6 0
(C)

3 double bonds alternating with 3 single bonds, making it a 6 sided ring!


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Solution 1 contains 3.5g of sodium chloride in 500 mL of water. Solution 2 contains 7.5g of glucose in 300 mL of water. If the a
meriva

Answer:

Answer is Object 2 (which has a density of 1.9 g/cm³).

Explanation;

   When object is floating, the weight of that object is less than the up thrust on it.

   When an object fully submerged and floating, then the weight of that object is equal to the up thrust on it.

   This is known as the Archemide's principle.

   Both up thrust and weight depends on the density. Hence, if the density of the solution is high, then the up thrust also high. If the density high, the the weight of the object also high.

   Hence, to sink the object in water, that object should be denser than water. Hence, answer is object 3 which has a higher density than water.

Explanation:

8 0
3 years ago
A laboratory requires 2.0 L of a 1.5 M solution of hydrochloric acid (HCl), but the only available HCl is a 12.0 M stock solutio
ira [324]
The amount of the solute is constant during dilution. So the mole number of HCl is 2*1.5=3 mole. The volume of HCl stock is 3/12=0.25 L. So using 0.25 L stock solution and dilute to 2.0 L.
6 0
3 years ago
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I really need help with this I would really appreciate it​
gulaghasi [49]
PV=nRT will give you the answer I think. I haven’t worked with a certain unit in that problem
3 0
4 years ago
- Equilibrium shifts for slightly soluble compounds The reaction for the formation of a saturated solution of silver bromide (Ag
RideAnS [48]

Answer:

1) Favor formation of reactant

2) Favor formation of product

3) Favor formation of product

4) Favor formation of product

5) Favor formation of product

Explanation:

The reaction is AgBr(s)--->Ag^{+}(aq)+Br^{-}(aq)

The reaction is endothermic

1. Adding hydrobromic acid (HBr)

It will increase the amount of bromide ion. Bromide ion is one of the product so it will favor formation of reactant.

2. Lowering the concentration of bromide (Br-) ions

As we are decreasing the the concentration of product it will favor formation of more products

3. Heating the concentrations

If we are heating the mixture, it will increase the temperature and it will favor endothermic reaction. Thus will favor formation of product.

4. Adding solid silver bromide (AgBr)

If we are adding silver bromide it means we are increasing the concentration of reactant, it will favor formation of products

5. Removing silver (Ag+) ions

Removing silver ions means we are decreasing the concentration of product thus it will favor formation of products.

3 0
3 years ago
In a neutral solution, the concentration of H+ is
Elan Coil [88]

Answer:

1 x 10^-7 or 7

Explanation:

pH=-log(H+)

pH+pOH=14

5 0
3 years ago
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