Question

Part F

Answer 1

At an equal time interval, acceleration increases with increase in velocity and it will maintain a positive value. When this value is compared to -9.8 m/s² (acceleration due to gravity), the value obtained will be greater than the value of acceleration due to gravity.

Generally, acceleration is defined as the change in velocity per change in time of motion.

Acceleration of an object at any given time, t, can be calculated using the following equations below;

$a = \frac{\Delta v}{\Delta t} = \frac{v-u}{t_2-t_1}$

where;

• v is final velocity at t₂
• u is the initial velocity at t₁
• t₂ is the final time of motion
• t₁ is the initial time of motion

From the formula above, we can conclude that at an equal time interval, acceleration increases with increase in velocity and it will maintain a positive value. When this value is compared to -9.8 m/s² (acceleration due to gravity), the value obtained will be greater than the value of acceleration due to gravity.

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Answer 2

Answer:

t an equal time interval, acceleration increases with increase in velocity and it will maintain a positive value. When this value is compared to -9.8 m/s² (acceleration due to gravity), the value obtained will be greater than the value of acceleration due to gravity.

Generally, acceleration is defined as the change in velocity per change in time of motion.

Acceleration of an object at any given time, t, can be calculated using the following equations below;

Explanation: