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3 years ago

How can he make the cart move faster?

Physics

2 answers:

emmasim [6.3K]3 years ago

7 0

I believe the correct answer is D) He can increase the force of his push

alukav5142 [94]3 years ago

4 0

D because force increase acceleration

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Si un automóvil logra una potencia util promedio de 250kw y se sabe que tiene un rendimiento energético del 25%. ¿Cuanta energia

Jet001 [13]

Answer:

W = 3.75 kJ

Explanation:

Power is defined by the relational

P = W / t

W = P t

the yield is 25% = 0.25

W = 0.25 Wo

W = 0.25 250 60

W = 3750 J

W = 3.75 kJ

8 0

3 years ago

During most of its lifetime, s star maintains an equilibrium size in which the inward force of gravity on each atom is balanced

frez [133]

Answer:

$r_f=137493m$

$v=8638940m/s$

Explanation:

During this process the mass $M=2\times10^{30}Kg$ will be considered constant. We start from a radius $r_i=7\times10^8m$ and a period $T_i=30\ days=(30)(24)(60)(60)s=2592000s$ . The final period is $T_f=0.1s$ .

Angular momentum <em>L</em> is conserved in this process. We can use the formula $L=I\omega$ , where I is the momentum of inertia (which for a solid sphere is $I=\frac{2mr^2}{5}$ ) and $\omega=\frac{2\pi }{T}$ is the angular velocity, so we can write the star's angular momentum as:

$L=I\omega=\frac{2mr^2}{5}\frac{2\pi }{T}=\frac{4\pi mr^2 }{5T}$

Since $L_f=L_i$ we have:

$\frac{4\pi mr_f^2 }{5T_f}=\frac{4\pi mr_i^2 }{5T_i}$

Which can be simplified as:

$\frac{r_f^2 }{T_f}=\frac{r_i^2 }{T_i}$

Which means:

$r_f=\sqrt{\frac{r_i^2 T_f}{T_i}}=r_i \sqrt{\frac{T_f}{T_i}}$

Which for our values is:

$r_f=r_i \sqrt{\frac{T_f}{T_i}}=(7\times10^8m) \sqrt{\frac{0.1s}{2592000s}}=137493m$

And we calculate the speed of a point on the equator by dividing the final circumference over the final period:

$v=\frac{C_f}{T_f}=\frac{2\pi r_f}{T_f}=\frac{2\pi (137493m)}{(0.1s)}=8638940m/s$

3 0

4 years ago

Is block b speeding up or slowing down once it is set into downward motion and the cat is on block a?

stepan [7]

Answer:

The answer is "Slowing down ".

Explanation:

please find the complete question in the attached file.

In this question, if the block B weight were accounted for by kinetic the friction of frame A, because the blocks pushed at a consistent speed throughout the beginning.

Afterward, on block A, the resistance intensity rises, which allows frames to also be negative, which is defined in the graph, that's why the answer Slowing down is correct.

6 0

3 years ago

Where is the centre of mass of a system of two particles is situated?

Sever21 [200]

Answer:

In a two particle system, the center of mass lies on the center of the line joining the two particles.

4 0

3 years ago

Planet X has three times the free-fall acceleration of Earth.

serious [3.7K]

Answer:

a) The ball goes one-third times higher on X

b) The ball goes three times higher on X.

Explanation:

As the initial velocity is the same than on Earth, but the free-fall acceleration is three times larger, this means that the only net force acting on the ball (gravity) will be three times larger, so it is clear that the ball will reach to a lower height, as it will slowed down more quickly.
Kinematically, as we know that the speed becomes zero when the ball reaches to the maximum height, we can use the following kinematic equation:

$v_{f} ^{2} - v_{o}^{2} = 2* \Delta h* g$

since vf = 0, solving for Δh, we have:

$\Delta h = h_{max} =\frac{v_{o} ^{2}}{2*g} (1)$

if v₀ₓ = v₀E, and gₓ = 3*gE, replacing in (1), we get:

Δhₓ = 1/3 * ΔhE

which confirms our intuitive reasoning.

Now, if the initial velocity is three times larger than the one on Earth, even the acceleration due to gravity is three times larger, we conclude that the ball will go higher than on Earth.
We can use the same kinematic equation as in (1) replacing Vox by 3*VoE, as follows:

$\Delta h = h_{max} =\frac{(3*v_{o}) ^{2}}{2*3*g} (2)$

Replacing the right side of (1) in (2), we get:

Δhx = 3* ΔhE

which confirms our intuitive reasoning also.

7 0

3 years ago