Answer:
I believe the answer is II and III
Explanation:
I'm not sure if III is right cause I cannot read the last word but I think it's OK.
Hope this helped :)
Explanation:
34.2g of C12H22O11 is dissolved in 180g of H20.
Molar mass of sucrose = 342g/mol
Moles of sucrose = 342 / 34.2 = 10 mol.
Molar mass of water = 18g/mol
Moles of water = 180 / 18 = 10 mol.
For hydrogen atoms, there are 22 * 10 in sucrose and 2 * 10 in water, which gives a total of 240.
For oxygen atoms, there are 11 * 10 in sucrose and 1 * 10 in water, which gives a total of 120.
Subtracting the mass of (flask+water) from the empty flask gives:
95.023 g - 85.135 g = 9.888 grams of water
Dividing this by the given volume of 10.00 mL water gives:
9.888 grams of water / 10.00 mL of water = 0.9888 g/mL of water
Therefore, based on this sample, the density of water is 0.9888 g/mL, which is close to the usually accepted approximation of 1 g/mL.
<u>Answer:</u> The pH of the cleaning compound is 10.44
<u>Explanation:</u>
pH is defined as the negative logarithm of hydrogen or hydronium ion concentration that are present in a solution.
The equation representing pH of the solution follows:
![pH=-\log[H^+]](https://tex.z-dn.net/?f=pH%3D-%5Clog%5BH%5E%2B%5D)
We are given:
![[H^+]=3.6\times 10^{-11}](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D3.6%5Ctimes%2010%5E%7B-11%7D)
Putting values in above equation, we get:
Hence, the pH of the cleaning compound is 10.44
