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Semmy [17]
2 years ago
7

A pure sample of a monoprotic acid is dissolved in water. the sample is titrated with sodium hydroxide solution. at the point wh

ere 20.0 ml of the naoh solution has been added, the ph is 4.15. the phenolphthalein endpoint of the titration is observed when 50.0 ml of naoh have been added. what is the pka of the acid
Chemistry
1 answer:
Yakvenalex [24]2 years ago
6 0

Answer:

21 22 23 24 25 26 27 28 29 30

Explanation:

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What does molecules form or make
noname [10]
A hydrogen atom forms one bond, an oxygen atom forms two, and carbon forms four bonds. 
7 0
3 years ago
Read 2 more answers
How does 2 Na (s) + Cl2 (g) = NaCl (s) represent the coefficient in the chemical equation
Elenna [48]

Answer:

The 2 would be placed in front of the reactant Na and in front of the product NaCl

2Na + Cl2 = 2NaCl

Explanation:

This is because the ratio of elements needs to be balanced on both sides.

On the reactants side, there are 2 Na molecules and 2 Cl molecules

On the products side, there are 2 Na molecules and 2 Cl molecules

So, now the equation is balanced

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3 years ago
Os etapas que devem sem compridas para obter separadamente os componentes (a as substâncias ) de uma mistura de água ,sal e arei
SashulF [63]

Answer:

The steps that must be long to obtain separately the components (to the substances) of a mixture of water, salt and sand, are respectively: A) filtration and siphoning B) decanting and siphoning C) simple filtration and distillation D) collection and decantation.

Simple filtration and Siphoning is the method. When an insoluble solid is present in a liquid. Filtration is the ideal method of separation,The sand is filtered by the filtered paper as water is allowed to pass through the filter paper into a beaker where the funnel which hold the filter paper emptied into.

Water molecules is Siphoned, pull by force of gravity through the sand, past  the filter paper to emerge as clean in the beaker below.

4 0
4 years ago
Which property of water helps it move upward by capillary action
zhannawk [14.2K]
It’s the water method that helps it
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3 years ago
Draw the products obtained from the reaction of 1 equivalent of HBr with 1 equivalent of 2,5-dimethyl-1,3,5-hexatriene. Draw the
fgiga [73]

Answer:

Here's what I get.

Explanation:

According to Markovnikov's rule, the H will add to a terminal carbon, generating three resonance stabilized carbocations.

The Br⁻ ion will add to any of the three carbocations.

There are three possible products:

  1. 5-bromo-2,5-dimethylhexa-1,3-triene (1)
  2. 3-bromo-2,5-dimethylhexa-1,4-triene (<em>2</em>)
  3. 1-bromo-2,5-dimethylhexa-2,4-triene (3)

6 0
3 years ago
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