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kolezko [41]
2 years ago
5

Describe what you would expect to observe, if anything, when a piece of nickel is placed in a solution of copper(II) nitrate. (s

elect all that apply)
a. Solid copper would form on the surface of the nickel metal.
b. The blue color of the solution would become darker.
c. Nickel atoms are converted to nickel ions in solution.
d. The blue color of the solution would become lighter.
e. No reaction would occur.
Chemistry
1 answer:
Tom [10]2 years ago
6 0

When a piece of nickel is placed in a solution of copper(II) nitrate:

a. Solid copper would form on the surface of the nickel metal.

c. Nickel atoms are converted to nickel ions in solution.

d. The blue color of the solution would become lighter.

Let's consider what happens when a piece of nickel is placed in a solution of copper(II) nitrate. Cu has a higher reduction potential than Ni, thus Cu will reduce and Ni will oxidize. This will be a single displacement redox reaction. The corresponding balanced molecular equation is:

Ni(s) + Cu(NO₃)₂(aq) ⇒ Ni(NO₃)₂(aq) + Cu(s)

The net ionic equation is:

Ni(s) + Cu²⁺(aq) ⇒ Ni²⁺(aq) + Cu(s)

<em>Describe what you would expect to observe, if anything, when a piece of nickel is placed in a solution of copper(II) nitrate.</em>

<em>a. Solid copper would form on the surface of the nickel metal.</em> YES. Solid copper will deposit on the surface of nickel metal.

<em>b. The blue color of the solution would become darker.</em> NO. The blue color, caused by Cu²⁺ ions, will become lighter, as their concentration decreases.

<em>c. Nickel atoms are converted to nickel ions in solution.</em> YES. Ni is oxidized to Ni²⁺.

<em>d. The blue color of the solution would become lighter.</em> YES. Due to the decrease in the concentration of Cu²⁺ ions.

<em>e. No reaction would occur.</em> NO.

When a piece of nickel is placed in a solution of copper(II) nitrate:

a. Solid copper would form on the surface of the nickel metal.

c. Nickel atoms are converted to nickel ions in solution.

d. The blue color of the solution would become lighter.

You can learn more about redox reactions here: brainly.com/question/13978139

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A 37.2 g sample of copper at 99.8 °C is carefully placed into an insulated container containing 188 g of water at 18.5 °C. Calcu
klasskru [66]

Answer:

T₂ = 19.95°C

Explanation:

From the law of conservation of energy:

Heat\ Lost\ by\ Copper = Heat\ Gained\ by\ Water\\m_cC_c\Delta T_c = m_wC_w\Delta T_w

where,

mc = mass of copper = 37.2 g

Cc = specific heat of copper = 0.385 J/g.°C

mw = mass of water = 188 g

Cw = specific heat of water = 4.184 J/g.°C

ΔTc = Change in temperature of copper = 99.8°C - T₂

ΔTw = Change in temperature of water = T₂ - 18.5°C

T₂ = Final Temperature at Equilibrium = ?

Therefore,

(37.2\ g)(0.385\ J/g.^oC)(99.8\ ^oC-T_2)=(188\ g)(4.184\ J/g.^oC)(T_2-18.5\ ^oC)\\99.8\ ^oC-T_2 = \frac{(188\ g)(4.184\ J/g.^oC)}{(37.2\ g)(0.385\ J/g.^oC)}(T_2-18.5\ ^oC)\\\\99.8\ ^oC-T_2 = (54.92) (T_2-18.5\ ^oC)\\54.92T_2+T_2 = 99.8\ ^oC + 1016.02\ ^oC\\\\T_2 = \frac{1115.82\ ^oC}{55.92}

<u>T₂ = 19.95°C</u>

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A chemical changes is not reversible
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Answer:

B. Increase the mass of one of the objects.

E. Decrease the distance between the objects.

Explanation:

To effect an increase in the gravitational force between two objects, the mass of both objects should be increased and the distance between them reduced.

This is derived from the Newton's law of universal gravitation:

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