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irakobra [83]
3 years ago
11

Atomic emission spectra are produced when the light emitted by an element passes through a prism. Which of the following stateme

nts is true regarding these spectra?
A. All elements produce the same atomic spectra.
B. Elements produce continuous spectra.
C. Elements produce spectra with only a few distinct lines.
Chemistry
1 answer:
xenn [34]3 years ago
3 0
Option C: elements produce spectra with only few distinct lines.

The spectra are not continuos and are different for every element. This permits to identify elements.
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Drinking energy drinks makes people more aggressive.
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Outcome (dependent) variable-drinking energy drinks

Test (independent) variable- more aggressive
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3 years ago
What type of particle has no mass or charge? <br> A) Alpha <br> B) Beta <br> C) Gamma <br> D) Proton
viva [34]

Answer:

Your answer would be C.

Explanation:

Gamma radiation, unlike alpha or beta, does not consist of any particles, instead consisting of a photon of energy being emitted from an unstable nucleus. Having no mass or charge, gamma radiation can travel much farther through air than alpha or beta, losing (on average) half its energy for every 500 feet.

4 0
3 years ago
Read 2 more answers
The equilibrium constant Kc for the reaction PCl3(g) + Cl2(g) ⇌ PCl5(g) is 49 at 230°C. If 0.70 mol of PCl3 is added to 0.70 mol
Ymorist [56]

Answer : The correct option is, (B) 0.11 M

Solution :

First we have to calculate the concentration PCl_3 and Cl_2.

\text{Concentration of }PCl_3=\frac{\text{Moles of }PCl_3}{\text{Volume of solution}}

\text{Concentration of }PCl_3=\frac{0.70moles}{1.0L}=0.70M

\text{Concentration of }Cl_2=\frac{\text{Moles of }Cl_2}{\text{Volume of solution}}

\text{Concentration of }Cl_2=\frac{0.70moles}{1.0L}=0.70M

The given equilibrium reaction is,

                            PCl_3(g)+Cl_2(g)\rightleftharpoons PCl_5(g)

Initially                 0.70        0.70              0

At equilibrium    (0.70-x)   (0.70-x)           x

The expression of K_c will be,

K_c=\frac{[PCl_5]}{[PCl_3][Cl_2]}

K_c=\frac{(x)}{(0.70-x)\times (0.70-x)}

Now put all the given values in the above expression, we get:

49=\frac{(x)}{(0.70-x)\times (0.70-x)}

By solving the term x, we get

x=0.59\text{ and }0.83

From the values of 'x' we conclude that, x = 0.83 can not more than initial concentration. So, the value of 'x' which is equal to 0.83 is not consider.

Thus, the concentration of PCl_3 at equilibrium = (0.70-x) = (0.70-0.59) = 0.11 M

The concentration of Cl_2 at equilibrium = (0.70-x) = (0.70-0.59) = 0.11 M

The concentration of PCl_5 at equilibrium = x = 0.59 M

Therefore, the concentration of PCl_3 at equilibrium is 0.11 M

3 0
4 years ago
Which of the four macromolecules are the largest
Kruka [31]
Lipid you can look up the chemical structures and lipids are the longest which make them the largest
5 0
3 years ago
By how much will the water temperature increases if 1046 J of heat energy are added. The specific heat of water is 4.184 J/g • °
Brilliant_brown [7]

Answer:

Option A

250 degrees Celcius

Explanation:

If 1046J of heat energy is added to water, the water will experience a rise in temperature, at a rate that is directly proportional to its specific heat capacity.

Mathematically, this can be seen as Q=C\Delta T

Where C = specific heat of water = 4.184 J/g • °C.

Q = heat energy = 1046 J

\Delta T =1046/4.148=250 degrees Celcius

Therefore, the increase in temperature that will be experienced, is for 250 degrees Celcius

8 0
3 years ago
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