Question

The pH of a 0.016-M aqueous solution of p-toluidine (CH3C6H4NH2) is 8.60. Calculate Kb.

Answer 1

From the calculations performed, the Kb of the reaction is 9.9 * 10^-10

What is Kb?

The term Kb refers to the base dissociation constant of a solution. We have the following information from the question;

pH of the solution = 8.60

concentration of p-toluidine =  0.016-M

Recall that  pOH = 14 - pH

pOH = 14 - 8.60 = 5.4

[OH] = Antilog (-5.4) = 3.98 * 10^-6 M

We have to set up the ICE table;

          CH3C6H4NH2(aq) + H2O(l) ⇄ CH3C6H4NH3^+(aq) + OH^-(aq)

I             0.016                                           0                                   0

C           -x                                                   +x                                  +x

E    0.016  - x                                            3.98 * 10^-6                3.98 * 10^-6

Hence;

Kb = [3.98 * 10^-6]^2/[0.016  - 3.98 * 10^-6]

Kb =  9.9 * 10^-10

Learn more about Kb: brainly.com/question/12726841