Answer:
Molar solubility of AgBr = 51.33 × 10⁻¹³
Explanation:
Given:
Amount of NaBr = 0.150 M
Ksp (AgBr) = 7.7 × 10⁻¹³
Find:
Molar solubility of AgBr
Computation:
Molar solubility of AgBr = Ksp (AgBr) / Amount of NaBr
Molar solubility of AgBr = 7.7 × 10⁻¹³ / 0.150
Molar solubility of AgBr = 51.33 × 10⁻¹³
Answer: A. is elliptical
B. IS inrregulur C. spiral
Explanation: this should be it
4X + 3O₂ = 2X₂O₃
n(X₂O₃)=0.02225 mol
m(X)=4.000 g
x - the molar mass of metal
m(X)/4x=n(X₂O₃)/2
x=m(X)/{2n(X₂O₃)}
x=4.000/{2*0.02225)=89.89 g/mol
X=Y (yttrium)
Answer:
E) Silver, mass = 420 g, d = 10.5 g/cm.
Explanation:
Hello,
In this case, since the density is defined by:
Given the mass and density, we compute the volume via:
Thus, for each vase we have:
A) 
B) 
C) 
D) 
E) 
In such a way, the largest volume corresponds to E) Silver, mass = 420 g, d = 10.5 g/cm.
Best regards.
5 types of air pollution would include: Carbon Monoxide, Lead, Nitrogen oxides, sulfur oxides. I only know those 4 actually… hope it helped
