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Lena [83]
3 years ago
15

The eyes of reptile pass a single visual signal to the brain when the visual receptors are struck by photons of wavelength of 85

0 nm. If a total energy of 3.15 x 10-14 J is required to trip the signal, what is the minimum number of photons that must strike the receptor?
Chemistry
1 answer:
WINSTONCH [101]3 years ago
7 0

Answer: The minimum number of photons that must strike the receptor is 135\times 10^3

Explanation:

The relation between energy and wavelength of light is given by Planck's equation, which is:

E=\frac{Nhc}{\lambda}

where,

E = energy of the light = 3.15\times 10^{-14}J

N= Number of photons = ?

h = Planck's constant =6.6\times 10^{-34}

c = speed of light = 3\times 10^8m/s

\lambda = wavelength of light =850nm=850\times 10^{-9}m     (1nm=10^{-9}m)

3.15\times 10^{-14}=\frac{N\times 6.6\times 10^{-34}\times 3\times 10^8}{850\times 10^{-9}m}

N=135\times 10^3

Thus the minimum number of photons that must strike the receptor is 135\times 10^3

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