= 6.42 × 10²²
(scientific notation)
= 6.42e22
(scientific e notation)
= 64.2 × 10²¹
(engineering notation)
(sextillion; prefix zetta- (Z))
= 64200000000000000000000
(real number)
Answer:
it is b just trust me man I know
Lets name one gas sample as A and other gas sample as B.
we can apply ideal gas law equation for both samples
PV = nRT
P - Pressure of A = Pressure of B
V - volume of A = volume of B
n - number of molecules of both A and B being equal is equivalent to number of moles of A = number of moles of B
R - universal gas constant
Tᵃ - temperature of A
Tᵇ - temperature of B
for gas A
PV = nRTᵃ --1)
for gas B
PV = nRTᵇ ---2)
when we divide both equations
1 = Tᵃ / Tᵇ
Tᵃ = Tᵇ
both temperatures are equal
temperature in Celsius + 273 = temperature in Kelvin
therefore 0 °C = 273 K
the correct answer is
A)
<span>The first gas sample has a temperature of 273 K, and the second gas sample has a temperature of 0 </span>°<span>C</span>
They both ask for an amount of something
