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Dmitry [639]
3 years ago
10

What type of subatomic particles are found in the cloud?

Chemistry
1 answer:
Novay_Z [31]3 years ago
8 0

Answer:

Electrons are particles that surround the nucleus of an atom like a cloud. As with protons and neutrons, electrons are essential to an atom's structure.

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In the presence of excess oxygen, methane gas burns in a constant-pressure system to yield carbon dioxide and water: CH4 (g) 2O2
Degger [83]

Answer:

The energy released will be -94.56 kJ or -94.6 kJ.

Explanation:

The molar mass of methane is 16g/mol

The given reaction is:

CH_{4}(g) + 2O_{2} (g) --> CO_{2} (g)+ 2H_{2}O(l)

the enthalpy of reaction is given as  ΔH = -890.0 kJ

This means that when one mole of methane undergoes combustion it gives this much of energy.

Now as given that the amount of methane combusted = 1.70g

The energy released will be:

=\frac{energy released by one moleXgiven mass}{molarmass} =\frac{-890X1.7}{16}= -94.56 kJ

7 0
3 years ago
Write out the recipe and list all the ingredients (including the measures) of your favorite dish.
arsen [322]

The recipe for an omelet are:

<u>Ingredients</u>

  • 1 Egg
  • Salt and pepper ( 1 tablespoon )
  • Butter ( 1 tablespoon )

<u>Recipe:</u>

  • Turn on the heat and place a pan on it.
  • Add butter to the pan.
  • Crack the egg and whisk it properly.
  • Add the whisked omelet onto the pan and stir.
  • Add salt and pepper.

<h3>How to illustrate the information?</h3>

When we turn on the heat and place the pan, a heat transfer takes place and heat transfers from one body to another.

When we add butter to the pan, then the temperature of the pan was more than that of the butter.

Since the melting point of butter was less than the temperature of the pan, the the melting of butter takes place.

When we add the egg, the evaporation of the liquid present in the egg yolk and the egg white takes place.

These are the chemical reactions depicted.

Learn more about recipe on:

brainly.com/question/21913357

#SPJ1

4 0
1 year ago
Consider a mixture of oil and water. What terms would you use to describe this mixture? Check all that apply. Heterogeneous homo
GenaCL600 [577]

A mixture of oil and water is:

Heterogeneous

immiscible

<h3>What type of mixture of oil and water is?</h3>

The water molecules attract each other, and the oil molecules stick together. That causes oil and water to form two separate layers. Water molecules pack closer together, so they sink to the bottom, leaving oil sitting on top of the water. The mixture can be called as Emulsion. It is an immiscible liquid and the mixture is heterogeneous as oil floats on top of water surface but do not mix with it.

Thus, correct options are Heterogeneous and immiscible.

Find more information about Mixture here:

brainly.com/question/498370

6 0
2 years ago
Read 2 more answers
Confirmatory test of oxygen meaning?
Darya [45]

Answer:

Oxygen supports combustion so a good method of testing for oxygen is to take a glowing splint and place it in a sample of gas, if it re-ignites the gas is oxygen. This is a simple but effective test for oxygen.

Explanation:

4 0
3 years ago
When a 3.25 g sample of solid sodium hydroxide was dissolved in a calorimeter in 100.0 g of water, the temperature rose from 23.
sertanlavr [38]

Answer : The enthalpy change for the solution is 42.8 kJ/mol

Explanation :

Heat released by the reaction = Heat absorbed by the calorimeter + Heat absorbed by the water

q=[q_1+q_2]

q=[c_1\times \Delta T+m\times c_2\times \Delta T]

where,

q = heat released by the reaction

q_1 = heat absorbed by the calorimeter

q_2 = heat absorbed by the water

c_1 = specific heat of calorimeter = 15.8J/^oC

c_2 = specific heat of water = 4.18J/g^oC

m = mass of water = 100.0 g

\Delta T = change in temperature = T_2-T_1=(32.0-23.9)=8.1^oC

Now put all the given values in the above formula, we get:

q=[(15.8J/^oC\times 8.1^oC)+(100.0g\times 4.18J/g^oC\times 8.1^oC)]

q=3513.8J=3.5138kJ        (1 kJ = 1000 J)

Now we have to calculate the enthalpy change for the solution.

\Delta H=\frac{q}{n}

where,

\Delta H = enthalpy change = ?

q = heat released = 3.5138 kJ

m = mass of NaOH = 3.25 g

Molar mass of NaOH = 40 g/mole

\text{Moles of }NaOH=\frac{\text{Mass of }NaOH}{\text{Molar mass of }NaOH}=\frac{3.25g}{40g/mole}=0.0812mole

Now,

\Delta H=\frac{3.5138kJ}{0.0821mole}=42.8kJ/mol

Therefore, the enthalpy change for the solution is 42.8 kJ/mol

4 0
3 years ago
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