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Anna71 [15]
2 years ago
8

A boy in a tower throws a ball a distance of 60 meters. If the ball is launched from 20 m above the ground, at what speed is the

ball thrown?
Physics
1 answer:
mezya [45]2 years ago
8 0

The speed the ball was projected upwards is 29.7 m/s.

The given parameters;

  • height in which the ball was thrown, h = 20 m
  • distance traveled by the ball, X = 60 m

The time of motion of the ball to travel to the given height is calculated as;

h = v_0_yt - \frac{1}{2} gt^2\\\\-20 = 0 - 0.5\times 9.8t^2\\\\-20 = -4.9t^2\\\\t^2 = \frac{20}{4.9} \\\\t^2 = 4.08\\\\t = \sqrt{4.08} \\\\t = 2.02\ s

The horizontal speed in which the ball was projected upwards is calculate as;

X = (v₀ₓ)t

60 = 2.02v₀ₓ

v_0_x = \frac{60}{2.02} \\\\v_0_x = 29.7 \ m/s

Thus, the speed the ball was projected upwards is 29.7 m/s.

Learn more here: brainly.com/question/20064545

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Explanation:

By the kinetic theory of gases, we have;

v_{rms} = \sqrt{\dfrac{3 \cdot R \cdot T}{MW} }

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Where;

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R = The universal gas constant

T = The temperature

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n = The number of moles

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1) When the balloon is placed in the refrigerator for  minutes, the temperature inside the balloon will drop and RMS speed will reduce, however due to the elastic wall of the balloon, the pressure will remain the same therefore the volume  will reduce and the balloon will shrink

2) When the balloon is placed on the kitchen counter, the temperature inside the balloon will rise leading to the increase in the RMS speed which will raise the pressure effect on the wall  of the balloon as the balloon is made of elastic material, as the pressure rises, the wall expands to keep the pressure constant and the volume occupied by the air particles will increase, the balloon will grow bigger and regain its shape.

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3 years ago
In the Daytona 500 auto race, a Ford Thunderbird and a Mercedes Benz are moving side by side down a straightaway at 78.5 m/s. Th
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FT is 1020.6 meters (1640.6 meters - 620 meters) far from MB

Explanation:

First you have to consider that the Ford Thunderbird (FT) follows a rectilinear motion with varying acceleration, while Mercedez Benz (MB) has a constant velocity (no acceleration). So if you finde the time spent by FT in each section, and the distance, then you will find the distance for MB.

1) Vf² = Vi² + 2ad, where Vf: final velocity, Vi: ionitial velocity, a: acceleration and d: distance.

For the first portion  (0 m/s)² = (78.5 m/s)² + 2a(250 m) ⇒

-(78.5 m/s)² / 2(250m) = a ⇒ a = -12.3 m/s².

Now, you can find the corresponding time for this section with the following formule: Vf = Vi + at ⇒ 0 m/s = 78.5 m/s + (-12.3 m/s²) t

⇒ t= (-78.5 m/s)/ (-12.3 m/s²) ⇒ t= 6.4 seconds.

2) Then FT spent 5 seconds in the pit.

3) The the FT accelerates until reach 78.5 m/s again in a distance of 370 m.

Vf² = Vi² + 2ad ⇒ (78.5 m/s)² = (0 m/s)² + 2a(370 m)

⇒ (78.5 m/s)²/ 2(370 m) = a ⇒ a = 8.3 m/s²

Then, Vf = Vi + at ⇒ 78.5 m/s = 0 m/2 + (8.3 m/s²) t

⇒ (78.5 m/s)/(8.3 m/s²) = t ⇒ t = 9.5 seconds.

4) Summarizing, the FT moves 620 meters (250 + 370 mts) in 20.9 seconds ( 6.4 s + 5 s + 9.5 s).

5) During this time, MB moves

Velocity = distance/ time ⇒ Velocity x time = Distance

⇒ Distance = (78.5 m/s) x  (20.9 seconds) ⇒ Distance = 1640.6 meters

6) Finally, the FT is 1020.6 meters (1640.6 meters - 620 meters) far from MB

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