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Art [367]
3 years ago
13

WhAT is the change IN THE entropy of 2.0kg of h2o molecules when transform at a constant pressure of 1 atm from water at 100 deg

rees celcius to steam at the same tEMPERATURE?
Physics
1 answer:
Fynjy0 [20]3 years ago
3 0

Answer:

The entropy change is 45.2 kJ/K.

Explanation:

mass of water at 100 C = 2 kg

Latent heat of vaporization, L = 2260 kJ/kg

Heat is

H = m L

H = 2 x 2260 = 4520 kJ

Entropy is given by

S = H/T = 4520/100 = 45.2 kJ/K

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A child of mass 46.2 kg sits on the edge of a merry-go-round with radius 1.9 m and moment of inertia 130.09 kg m2 . The merrygo-
Vedmedyk [2.9K]

Answer:

The angular velocity is w_f = 4.503 \  rad/s

Explanation:

From the question we are told that

   The mass of the child is  m_c  =  46.2 \ kg

    The radius of the merry go round is  r =  1.9 \ m

     The moment of inertia of the merry go round is I_m =  130.09 \  kg \cdot  m^2

      The angular velocity of the merry-go round is  w =  2.4 \ rad/s

       The position of the child from the center of the merry-go-round is  x = 0.779 \ m

According to the law of angular momentum conservation

    The initial angular momentum  =  final  angular momentum

So  

       L_i  =  L_f

=>     I_i w_i  =  I_fw_f

Now   I_i is the initial moment of inertia of the system which is mathematically represented as

          I_i  = I_m + I_{b_1}

Where  I_{b_i} is the initial moment of inertia of the boy which is mathematically evaluated as

      I_{b_i} =  m_c * r

substituting values

      I_{b_i} =  46.2 *  1.9^2

      I_{b_i} =  166.8 \ kg \cdot m^2

Thus

   I_i  =130.09 + 166.8        

   I_i  = 296.9 \ kg \cdot m^2      

Thus  

     I_i * w_i  =L_i=  296.9 * 2.4

       L_i  = 712.5 \ kg \cdot m^2/s

Now  

     I_f =  I_m  + I_{b_f }

Where  I_{b_f} is the final  moment of inertia of the boy which is mathematically evaluated as

         I_{b_f} =  m_c * x

substituting values

         I_{b_f} =  46.2 * 0.779^2

         I_{b_f} =  28.03  kg \cdot m^2

Thus

      I_f =  130.09 + 28.03

      I_f =  158.12 \ kg \ m^2

Thus

     L_f  =  158.12 * w_f

Hence

      712.5  =  158.12 * w_f

       w_f = 4.503 \  rad/s

8 0
3 years ago
A stone was dropped off a cliff and hit the ground with a speed of 136 ft/s. what is the height of the cliff? (use 32 ft/s2 for
mina [271]
<span>(v1)^2=(v0)^2-2ad; v1= final velocity; v0= initial velocity; a=gravitational constant;d=distance Since the stone was dropped we know v0=0. (v1)^2=2ad (136)^2=2(32)d d=(136)^2/(2*32) d=289ft</span>
7 0
3 years ago
The negative will be __________ to the positive. Therefore, they are pulling __________ each other, and creating and electrical
Ierofanga [76]

Answer:

attracted... (not sure) close to...

3 0
2 years ago
What is the tangential speed of a point on a wheel of a car if the point is located 0.114 m from the axis of rotation; and the w
Svetach [21]

Answer:

Tangential speed = R * w  where w is the angular speed

For a wheel   v = .114 m * 6.53 / sec = .744 m/s

Note that this is the tangential speed - If the wheel were moving at speed V then as viewed from the ground you have

top V + v

bottom   V - v

That is the wheel also has speed due to the speed of the axle (axis of rotation)

3 0
3 years ago
According to the law of conservation of energy, how are potential energy and kinetic energy related?
frutty [35]
Your answer should be A, because every reaction has an equal opposite reaction
6 0
3 years ago
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