Answer:
The angular velocity is
Explanation:
From the question we are told that
The mass of the child is 
The radius of the merry go round is 
The moment of inertia of the merry go round is 
The angular velocity of the merry-go round is 
The position of the child from the center of the merry-go-round is 
According to the law of angular momentum conservation
The initial angular momentum = final angular momentum
So

=> 
Now
is the initial moment of inertia of the system which is mathematically represented as

Where
is the initial moment of inertia of the boy which is mathematically evaluated as

substituting values


Thus
Thus


Now

Where
is the final moment of inertia of the boy which is mathematically evaluated as

substituting values


Thus


Thus

Hence


<span>(v1)^2=(v0)^2-2ad; v1= final velocity; v0= initial velocity; a=gravitational constant;d=distance
Since the stone was dropped we know v0=0.
(v1)^2=2ad
(136)^2=2(32)d
d=(136)^2/(2*32)
d=289ft</span>
Answer:
Tangential speed = R * w where w is the angular speed
For a wheel v = .114 m * 6.53 / sec = .744 m/s
Note that this is the tangential speed - If the wheel were moving at speed V then as viewed from the ground you have
top V + v
bottom V - v
That is the wheel also has speed due to the speed of the axle (axis of rotation)
Your answer should be A, because every reaction has an equal opposite reaction