Ever seen a waterfall ? what do you think happens when all that water slams into the ground below ? same as when you turn a hosepipe on a flowerbed.
also, there's hydraulic cracking where water gets into cracks and freezes, splitting rocks apart.
fast moving water can carry sediment and roll rocks along the bottom. if the water slows down, it drops the rocks and heavier sediment. if it floods a field, say, then drains away, the grass will also filter smaller particles out, or the water might evaporate and leave fine sediment behind.
The equation to be used are:
PM = ρRT
PV = nRT
where
P is pressure, M is molar mass, ρ is density, R is universal gas constant (8.314 J/mol·K), T is absolute temperature, V is volume and n is number of moles
The density of air at 23.5°C, from literature, is 1.19035 kg/m³. Its molar mass is 0.029 kg/mol.
PM = ρRT
P(0.029 kg/mol) = (1.19035 kg/m³)(8.314 J/mol·K)(23.5+273 K)
P = 101,183.9 Pa
n = 0.587 g * 1 kg/1000 g * 1 mol/0.029 kg = 0.02024 mol
(101,183.9 Pa)V = (0.02024 mol)(8.314 J/mol·K)(23.5+273 K)
Solving for V,
V = 4.931×10⁻⁴ m³
Since 1 m³ = 1000 L
V = 4.931×10⁻⁴ m³ * 1000
V = 0.493 L
The answer is (3) moles of solute per liter of solution. That is what the definition of molarity of a solution means. The equation is concentration = mol number of solute/ volume of solution.
If you're looking for "what rocks are formed by changes..." it's Igneous Rocks.
Answer:
1.3g/L is the density of the air
Explanation:
The room is full of air, the space that the air occupy is:
500 cm x 400 cm x 250 cm = 5.00x10⁷ cm³
The density of a substance is defined as the ratio between the mass of the substance and the space that occupy. We can express the density of air in g/L:
<em>Grams air:</em>
65 kg * (1000g / 1kg) = 65000g
<em>Liters:</em>
5.00x10⁷ cm³ * (1L / 1000cm³) = 50000L
<em>Density:</em>
65000g / 50000L =
<h3>1.3g/L is the density of the air </h3>
