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nlexa [21]
3 years ago
14

How many liters would you need to make a 1 M solution if you have 6 mol of Sodium Hydroxide

Chemistry
1 answer:
Harlamova29_29 [7]3 years ago
6 0
<h3>ANSWER</h3>

<h2><em>C</em><em> </em><em>-</em><em> </em><em>6</em></h2>

<em><u>One mole of NaOH = 40g NaOH</u></em>

<em><u>One mole of NaOH = 40g NaOHso to prepare 1M NaOH we need to dissolve 40g NaOH in water</u></em>

<em><u>One mole of NaOH = 40g NaOHso to prepare 1M NaOH we need to dissolve 40g NaOH in wateraccording to the given data,</u></em>

<em><u>One mole of NaOH = 40g NaOHso to prepare 1M NaOH we need to dissolve 40g NaOH in wateraccording to the given data,we have 6 moles of NaOH so we need 6 litres of Water olto prepare 1M Solution</u></em>

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Aryan want to deposit silver on an iron spoon using silver nitrate as electrolyte. Which terminal of the battery he should conne
34kurt

Silver from the anode gets dissolved to reach the cathode, where the spoon will be plated.

<h3>What is electroplating?</h3>

Electroplating is a way of electrolysis, where a thin layer of metal is used to plate a determined object. It is a kinda process to purify a material you want.

The anode contains the metal you want to plate with, in this case, the Ag.

The anode contains the half-reaction of oxidation so:

Ag(s) → Ag ⁺ (aq)  +  e⁻

In the cathode, you have the spoon, which it takes place the half-reaction of reduction:

Ag ⁺ (aq)  +  e⁻  →  Ag(s)

The electrolytic cell, where the redox reaction takes place, must be filled with a AgNO₃ solution.

Silver from the anode gets dissolved to reach the cathode, where the spoon will be plated.

Learn more about the electroplating here:

brainly.com/question/20112817

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8 0
2 years ago
How many moles of phosphoric acid are there in 658 grams of phosphoric acid?
vovangra [49]
<span>The molecular formula for phosphoric acid is H3PO4 and has 97.994 grams per mol. In a sample of 658 grams of phosphoric acid, there are 6.71 mols of phosphoric acid.</span>
8 0
3 years ago
How many moles of oxygen are needed for the complete combustion of 29.2 grams of acetylene?
podryga [215]

Moles of Oxygen= 2.8075 moles

<h3>Further explanation</h3>

Given

29.2 grams of acetylene

Required

moles of Oxygen

Solution

Reaction(Combustion of Acetylene) :

2 C₂H₂ (g) + 5 O₂ (g) ⇒ 4CO₂ (g) + 2H₂O (g)

Mol of Acetylene :

= mass : MW Acetylene

= 29.2 g : 26 g/mol

= 1.123

From equation, mol ratio of Acetylene(C₂H₂) : O₂ = 2 : 5, so mol O₂ :

= 5/2 x mol C₂H₂

= 5/2 x 1.123

= 2.8075 moles

7 0
3 years ago
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4 0
3 years ago
During complete combustion, natural gas combines with oxygen to produce _____.
natta225 [31]
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6 0
3 years ago
Read 2 more answers
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