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3 years ago

How many liters would you need to make a 1 M solution if you have 6 mol of Sodium Hydroxide

Chemistry

1 answer:

Harlamova29_29 [7]3 years ago

6 0

<h3>ANSWER</h3>

One mole of NaOH = 40g NaOH

One mole of NaOH = 40g NaOHso to prepare 1M NaOH we need to dissolve 40g NaOH in water

One mole of NaOH = 40g NaOHso to prepare 1M NaOH we need to dissolve 40g NaOH in wateraccording to the given data,

One mole of NaOH = 40g NaOHso to prepare 1M NaOH we need to dissolve 40g NaOH in wateraccording to the given data,we have 6 moles of NaOH so we need 6 litres of Water olto prepare 1M Solution

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A 100 gram block is placed on a scale that is known to have a 12% error. What will the scale read?

sesenic [268]

The scale will read 112 grams.

Why?

Since we already know the percent error of the scale (12%) and we also know the mass of the block that is placed on the scale, we can calculate what will be the read of the scale by using the following formula:

$ScaleRead=100g+(100g*\frac{12}{100})=100g+(100g*0.12)=100g+12g\\\\ScaleRead=112g$

We can see that the scale will read 112 grams.

Let's verify that we are right by using the following formula to verify if the obtained value for the scale read will be 12%:

$PercentError=\frac{ActualValue-RealValue}{RealValue}*100=\frac{112g-100g}{100g}*100\\\\PercentError=\frac{12g}{100g}*100=0.12*100=12(percent)$

Hence, we can see that the scale will read 112 grams.

Have a nice day!

7 0

4 years ago

Calculate Δ H o for the reaction. CH3OH + HCl → CH3Cl + H2O answer is in kJ/mol .

Nimfa-mama [501]

Answer:

$\Delta H=-28.08 \frac{kJ}{mol}$

Explanation:

Hello,

This types of reactions are likely to be carried out in gaseous phase as it is easier to induce reactions, therefore, for us to compute the change in the enthalpy of this reaction we should write the formation enthalpy of gaseous methanol, hydrogen chloride, methyl chloride and water as -205.1, -92.3, -83.68 and -241.8 kJ/mol respectively. Then, the reaction enthalpy for this reaction is:

$\Delta H=\Delta _fH_{CH_3Cl}+\Delta _fH_{H_2O}-\Delta _fH_{CH_3OH}-\Delta _fH_{HCl}\\\\\Delta H=-83.68\frac{kJ}{mol}-241.8\frac{kJ}{mol}-(-205.1\frac{kJ}{mol})-(-92.3\frac{kJ}{mol} )\\\\\Delta H=-28.08 \frac{kJ}{mol}$

Which accounts for an exothermic chemical reaction.

Regards.

7 0

4 years ago

What do you do if you receive a chemical splash to the eyes? A. Do not rub or wipe the eyes. B. All of the above. C. At the eyew

Aleksandr [31]

Explanation:

E let the water flow into the eye continuously for fifteen minutes or until medical help arrives.

5 0

4 years ago

A sample of an unknown biochemical compound is found to have a percent composition of 45.46 percent carbon, 7.63 percent hydroge

Leona [35]

Answer:

Formular = C₅H₁₁NO₃

Explanation:

The empirical formular is the simplest formular of a compound can have.

We use the steps below to obtain the empirical formular;

Step 1: Obtain the mass of each element present in grams. Element % = mass in g = m.

Carbon = 45.46% = 45.46g

Hydrogen = 7.63% = 7.63g

Nitrogen = 10% = 10g

Oxygen = 100% - (45.46% + 7.63% + 10%) = 36.31% = 36.31g

Step 2: Determine the number of moles of each type of atom present.

Molar amount (M) = m/atomic mass

Carbon = 45.46 / 12 = 3.7883

Hydrogen = 7.63 / 1 = 7.63

Nitrogen = 10 / 14 = 0.7143

Oxygen = 36.91 / 16 = 2.3069

Step 3: Divide the number of moles of each element by the smallest number of moles. Smallest = 0.7143

Carbon = 3.7883 / 0.7143 = 5.3035

Hydrogen = 7.63 / 0.7143 = 10.67

Nitrogen = 0.7143 / 0.7143 = 1

Oxygen = 2.2693 / 0.7143 = 3.1770

Step 4: Convert numbers to whole numbers

Carbon = 5

Hydrogen = 11

Nitrogen = 1

Oxygen = 3

Formular = C₅H₁₁NO₃

3 0

4 years ago

A bond based on intermolecular forces between hydrogen and fluorine, nitrogen, or oxygen is a _____.

Anuta_ua [19.1K]

Hydrogen Bond is the bond based on intermolecular forces between H and F O and N

7 0

4 years ago

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