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finlep [7]
2 years ago
6

A ball is hit so that it accelerates at 10 m/s2. The ball hits a glove with a force of 5 N. What is the mass of the ball?

Physics
1 answer:
jenyasd209 [6]2 years ago
8 0

Answer:

0.5 kg

Explanation:

» <u>Concepts</u>

Newton's second law, the Law of Acceleration, states that F = ma, where F = Force in Newtons, m = mass in kg, and a = acceleration in m/s^2.

» <u>Application</u>

We are asked to find the mass of the ball using the equation F = ma. We're also given the force and acceleration, so the equation looks like 5 = 10(m).

» <u>Solution</u>

Step 1: Divide both sides by 10.

  • 5/10=10m/10
  • m=0.5

Thus, the mass of the ball is 0.5 kg.

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Bill and Ted are standing on a bridge 40 ft above a river. Bill drops a stone, while Ted decides to throw a stone downward at 10
USPshnik [31]

Answer:

D.

Explanation:

In order to know how long after Bill released his rock should Ted throw his if they want the stones to hit the water simultanously, we need to calculate the time needed to hit the water to both rocks independent each other, and just take the difference.

For the rock dropped by Bill, as the only influence on it is gravity (accelerating it downwards with an acceleration equal to g), and v₀ =0, we can use the following kinematic equation:

y = \frac{1}{2} * g * t^{2}

where y = height = 40 ft.

As all the parameters are given in SI units, it is  advisable to convert this value to m, as follows:

y = 40 ft*\frac{0.3048m}{1 ft} = 12.2 m

Now, we can solve for t, as follows:

t = \sqrt{\frac{2*y}{g}} =  \sqrt{\frac{2*12.2m}{9.8m/s2}} = 1.58 s

For the rock thrown down at 10 m/s, the kinematic equation we just have used becomes:

y = v0*t +\frac{1}{2} * g * t^{2}

This leaves us a quadratic equation on t, as follows:

t = \frac{-10m/s}{9.8m/s2} +/- \sqrt{10m/s^{2} -4*4.9m/s2*(-12.2m)} = -1.02 s +/- 1.88s

Taking the positive root, we have:

t = -1.02 s + 1.88 s = 0.86 s

So, in order to get that both rocks hit the water at the same time, Ted will need to wait the difference between both times:

Δt = 0.86 s - 1.58s = -0.72 s

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3 years ago
5 ejemplos de ondas mecánicas PORFAVOR!!
kupik [55]

Answer: Una onda de sonido es un ejemplo de onda mecánica. Las ondas sonoras son incapaces de viajar a través del vacío. Las ondas furtivas, las ondas del agua, las ondas de los estadios y las ondas para saltar la cuerda son otros ejemplos de ondas mecánicas; cada uno requiere algún medio para existir.

English Translation: A sound wave is an example of a mechanical wave. Sound waves are incapable of traveling through a vacuum. Slinky waves, water waves, stadium waves, and jump rope waves are other examples of mechanical waves; each requires some medium in order to exist.

Explanation:

6 0
2 years ago
a large bottle contains a number of medicinal tablets each having a mass of 250mg the mass of all the tablets is 0.5kg calculate
lys-0071 [83]

Considering the change of units and rule of three, the number of tablets in the bottle is 2,000.

First of all, you know that each medicinal tablet has a mass of 250 mg, while the mass of all tablets is 0.5 kg. You can see that the measurements are in different units of measurement, so you must make a change of units so that they are in the same units.

So, knowing that 1 kg is equal to 1,000,000 mg, you can apply the following rule of three: if 1 kg is equal to 1,000,000 mg, 0.5 kg is equal to how many mg?

1 kg ⇒ 1,000,000 mg

0.5 kg ⇒ x mg

So: x=\frac{0.5 kgx1,000,000 mg}{1 kg}

<u><em>x= 500,000 mg</em></u>

Then, you know that each medicinal tablet has a mass of 250 mg, while the mass of all tablets is 500,000 mg. Now that the values ​​are in the same units, to calculate the number of medicinal tablets you must apply the following rule of three: if 1 tablet has a mass of 250 mg, how many tablets have a mass of 500,000 mg?

number of medicinal tablets=\frac{500,000 mgx1 tablet}{250 mg}

<u><em>number of medicinal tablets= 2,000</em></u>

Finally, the number of tablets in the bottle is 2,000.

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