Question

As a certain object falls, its position s (in meters) above ground after t seconds is given by s(t)=20-5t^2. Whats the average velocity of the object on the interval from t=1 to the time .5 seconds later?? from t=1 to the time .1 seconds later?

Answer 1

The average velocity of the object would be :

[s (1.5) - s (1)] /  0.5

= [8.75 -15] / 0.5

= 12.5 m/s

Hope this helps