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Nataliya [291]
4 years ago
10

As a certain object falls, its position s (in meters) above ground after t seconds is given by s(t)=20-5t^2. Whats the average v

elocity of the object on the interval from t=1 to the time .5 seconds later?? from t=1 to the time .1 seconds later?
Physics
1 answer:
denpristay [2]4 years ago
3 0
The average velocity of the object would be :

[s (1.5) - s (1)] /  0.5

= [8.75 -15] / 0.5

= 12.5 m/s

Hope this helps
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initial speed of 226000 m/s

acceleration of 4.0 x 1014 m/s2,

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What is Acceleration?

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  • A point or an object moving in a straight line is accelerated if it speeds up or slows down.
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As we have to find the time taken, the formula can be altered as,

t = \frac{v-u}{a}

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Substituting all the given values,

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Substituting numbers into the equation,

F_E=(8.98755\cdot 10^9 Nm^2 C^{-2})\frac{(1.602\cdot 10^{-19}C)^2}{(3 m)^2}=2.56\cdot 10^{-19}N

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