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Nataliya [291]
3 years ago
10

As a certain object falls, its position s (in meters) above ground after t seconds is given by s(t)=20-5t^2. Whats the average v

elocity of the object on the interval from t=1 to the time .5 seconds later?? from t=1 to the time .1 seconds later?
Physics
1 answer:
denpristay [2]3 years ago
3 0
The average velocity of the object would be :

[s (1.5) - s (1)] /  0.5

= [8.75 -15] / 0.5

= 12.5 m/s

Hope this helps
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Answer:

Part a)

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Part b)

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Explanation:

Part a)

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f = \frac{3 \times 10^8}{656 \times 10^{-9}}

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Part b)

As we know that the refractive index of water is given as

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so the wavelength in the water medium is given as

\lambda_w = \frac{\lambda}{\mu_w}

\lambda_w = \frac{656 nm}{4/3}

\lambda_w = 492 nm

Similarly the refractive index of glass is given as

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so the wavelength in the glass medium is given as

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Part c)

Speed of the wave in water is given as

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v_g = \frac{c}{\mu_g}

v_g = \frac{3 \times 10^8}{3/2}

v_g = 2 \times 10^8 m/s

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